 | John Fair Stoddard - Arithmetic - 1856 - 312 pages
...things remaining the same. Hence, to find the rate per cent., the remaining three things being given ; Divide the given interest, by the interest of the given principal, at 1 per cent., for the given time. 2. The interest of $120 for 2 years 9 months and 12 days, is $13'36.... | |
 | Benjamin Greenleaf - Arithmetic - 1857 - 452 pages
...produce $ 1 20 interest there will be required as many years as 30 is contained times in 120, or 4 years. RULE. — Divide the given interest by the interest of the given principal for 1 year. EXAMPLES. 2. How long must $ 120 be on interest, at 8£ per cent., to gain $ 13.20 ? Ans.... | |
 | Charles Guilford Burnham - 1857 - 342 pages
...of the interest for 1 year, is to the given interest, as 1 year is to the time required. Hence the RULE. Divide the given interest by the interest of the given principal for 1 year, and the quotient will be the answer. 2. la what time will $240 gain $4.80, at 6 per cent.... | |
 | Benjamin Greenleaf - Arithmetic - 1857 - 336 pages
...many years to gain $36 as $18 is contained times in $36. Thus, $36 -T- $18 = 2 years for the answer. RULE. — Divide the given interest by the interest of the given principal for 1 year, and the quotient will be the time. EXAMPLES FOR PRACTICE. 2. If the interest of $140 at... | |
 | Charles Guilford Burnham - Arithmetic - 1857 - 328 pages
...of the interest for 1 year, is to the given interest, as 1 year is to the time required. Hence the RULE. Divide the given interest by the interest of the given principal for 1 year, and the quotient will be the answer. 2. In what time will $240 gain $4.80, at 6 per cent.... | |
 | Benjamin Greenleaf - Arithmetic - 1858 - 458 pages
...cent. ; then the required rate will be as many per cent, as 20 is contained times in 120, or 6 per cent RULE. — Divide the given interest by the interest of the given principal at 1 per cent, for the given time. EXAMPLES. 2. The interest of $ 144 for 1 year is $ 10.08 ; what is... | |
 | Benjamin Greenleaf - Arithmetic - 1858 - 472 pages
...produce $ 1 20 interest there will be required as many years as 30 is contained times in 120, or 4 years. RULE. — Divide the given interest by the interest of the given principal for 1 year. EXAMPLES. 2. How long must $ 120 be on interest, at 8£ per cent., to gain $ 13.20 ? Ans.... | |
 | James B. Dodd - Arithmetic - 1859 - 368 pages
...Principal, at 1 per cent., for the given time. 2. The Time, in years, months, or days, is found by dividing the given Interest by the interest of the given Principal, at the given rate, for 1 year, month, or day, respectively. ^jj 32. At what rate per cent. would $250 amount to $287.50 in... | |
 | Benjamin Greenleaf - Arithmetic - 1861 - 338 pages
...require as many years to gain $36 as $18 is contained times iu $36, which gives 2 years for the answer. RULE. — Divide the given interest by the interest of the given principal for 1 year, and the quotient will be the time. EXAMPLES FOR PRACTICE. 2. If the interest of $140 at... | |
 | Benjamin Greenleaf - Arithmetic - 1871 - 350 pages
...years. «equir(! as Jany ye|rs to gain , 36 3 6-°0 as $ 18 is contained times in $ 36, or 2 years. RULE. — Divide the given interest by the interest of the given principal for 1 year, and the quotient will be the time. EXAMPLES FOR PRACTICE. 2. If the interest of $140 at... | |
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RULE. Divide the given interest by the interest of the given principal for 1 year, and the quotient will be the answer. 
