 FBC ; and because the two sides AB, BD are equal to the two FB, BC, each to each, and the angle DBA equal to the angle FBC ; therefore the base AD is equal to the base FC, and the triangle ABD to the triangle FBC.  Elements of Geometry: With Notes - Page 179by John Radford Young - 1827 - 208 pagesFull view - About this book
 | Euclid, Isaac Todhunter - Euclid's Elements - 1883 - 428 pages
...Add to each the angle ABC. Therefore the whole angle DBA is equal to the whole angle FBC. [Axiom 2. And because the two sides AB, BD are equal to the two sides FB, BC, each to each ; [Definition 30. and the angle DBA is equal to the angle FBC • therefore... | |
 | Euclides - 1884 - 182 pages
...right angle ; add to each the angle ABC ; then the whole angle DBA is equal to the whole FBC. (Ax. 2) And because the two sides AB, BD are equal to the two FB, BC, each to each, and the included angle ABD is equal to the includedangle FBC; therefore the triangle ABD is equal to the triangle... | |
 | John William Norie, J. W. Saul - Nautical astronomy - 1917 - 642 pages
...Add to each of these angles the angle ABC, therefore the whole angle DBA is equal to the whole angle FBC ; and because the two sides AB, BD, are equal to the two sides FB, B C. each to each, and the included angle ABD is equal to the included angle FBC, therefore... | |
 | 164 pages
...the whole DBA is equal to the whole FBC. And since DB is equal to BC, and FB to BA, the two DB, BA are equal to the two FB, BC, each to each ; and the angle DBA is equal to the angle FBC. Therefore the base AD is equal to the base FC ; and the triangle ABD is... | |
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