 FBC ; and because the two sides AB, BD are equal to the two FB, BC, each to each, and the angle DBA equal to the angle FBC ; therefore the base AD is equal to the base FC, and the triangle ABD to the triangle FBC.  Elements of Geometry: With Notes - Page 179by John Radford Young - 1827 - 208 pagesFull view - About this book
 | Euclid, Robert Simson - Geometry - 1829 - 548 pages
...being a right angle, add to each the angle ABC, and the whole angle DBA is equal (2. Ax.) to the vyhole FBC : and because the two sides AB, BD are equal to the two FB, BC, each to each, and theangle DBA equal to 'the angle FBC ; therefore the base AD isequal (4. 1.) to the base FC, and the... | |
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...the whole angle DBA will be equal (2. Ax. ) to the whole FBC; and because the two sides AB, BD,are equal to the two FB, BC each to each, and the angle DBA equal to the angle FBC, thereH fore the base AD is equal (4. 1.) to the base FC, and the triangle ABD to the triangle FBC.... | |
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...them being a right angle, adding to each the angle ABC; the whole angle DBA will be equal (2. Ax.)to the whole FBC ; and because the two sides AB, BD,...BC each to each, •and the angle DBA equal to the H angle FBC, therefore the base AD is equal (4. 1,) ta the base FC, and the triangle ABD to the triangle... | |
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