 | 1900 - 728 pages
...the base, or to the base extended. Thus, in Figs. 33 and 34, BD is the altitude of the triangles ABC. In an isosceles triangle, the angles opposite the equal sides are equal. Thus, in Fig. 35, AB = BC; hence, angle C — angle A. In any isosceles triangle, if a perpendicular... | |
 | International Correspondence Schools - Coal mines and mining - 1900 - 732 pages
...base, or to the base extended. Thus, in Figs. 33 and altitude in BD is the _ of the triangles ABC. . In an isosceles triangle, the angles opposite the equal sides are equal. Thus, in Fig. 35, AB — BC; hence, angle C = angle A. In any isosceles triangle, if a perpendicular... | |
 | Adelia Roberts Hornbrook - Arithmetic - 1900 - 428 pages
...isosceles triangle so that the equal sides coincide. Can you see that the following statement is true ? In an isosceles triangle the angles opposite the equal sides are equal. 352. How many degrees are there in each angle of the isosceles triangle ABC? Explain. 353. How many... | |
 | Alan Sanders - Geometry, Modern - 1901 - 260 pages
...of the other pair of vertical angles. Find the values of the four angles. PROPOSITION X. THEOREM 81. In an isosceles triangle, the angles opposite the equal sides are equal. Let ABC be an isosceles A, having AB = BC. To Prove Z A = Z C. Proof. Draw BD bisecting AC. (§ 55.) B and D are each equally... | |
 | Henry Parker Manning - Geometry, Non-Euclidean - 1901 - 122 pages
...the included angle, of one equal, respectively, to the corresponding parts of the other. 4. Theorem. In an isosceles triangle the angles opposite the equal sides are equal. Bisect the angle at the vertex and use (3). 5. Theorem. The perpendiculars erected at the middle points... | |
 | Thomas Franklin Holgate - Geometry - 1901 - 462 pages
...third side has also the greater included angle. § 80. 9. THEOREMS ON THE PROPERTIES OF TRIANGLES. (1) In an isosceles triangle, the angles opposite the equal sides are equal. § 48. (2) The straight line which bisects the vertical angle of an isosceles triangle also bisects... | |
 | Henry Parker Manning - Geometry, Non-Euclidean - 1901 - 116 pages
...the included anyle, of one equal, respectively, to the corresponding parts of the other. 4. Theorem. In an isosceles triangle the angles opposite the equal sides are equal. Bisect the angle at the vertex and use (3). 5. Theorem. The perpendiculars erected at the middle points... | |
 | Edward Brooks - Geometry, Modern - 1901 - 278 pages
...triangles coincide in all their parts and are equal. Therefore, etc. PROPOSITION XXI. — THEOREM. In an isosceles triangle the angles opposite the equal sides are equal. Given. — Let ABC be an isosceles triangle having the side AC equal to the side BC. To Prove. —... | |
 | Henry Parker Manning - Geometry, Non-Euclidean - 1901 - 120 pages
...the included angle, of one Kqual, respectively, to the corresponding parts of the other. 4. Theorem. In an isosceles triangle the angles opposite the equal sides are equal. Bisect the angle at the vertex and use (3). 5. Theorem. The perpendiculars erected at the middle points... | |
 | George Albert Wentworth - Geometry, Solid - 1902 - 248 pages
...angle of the other. 144. Two right triangles are equal if their legs are equal, each to each. 145. In an isosceles triangle the angles opposite the equal sides are equal. 147. If two angles of a triangle are equal, the sides opposite the equal angles are equal, and the... | |
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In an isosceles triangle, the angles opposite the equal sides are equal. 
