...+ b, that is, three times the part of the root already found. Moreover, we must add such a quantity to the second column as to obtain there three times...found. This is conveniently effected thus; we have (3a + i)&| already in the second column (За + b) b, and °a + oab + b > below that За2 + Заб...

...column, and add the last three lines in this column; thus we obtain I2xf — 36ся3 + 27cV, which is three times the square of the part of the root already found. Now divide the remainder in the third column by the expression just obtained, and we arrive at сг...

...remainder, the first term of the second remainder is 126- 2 a 4 . To form the new trial divisor, we take three times the square of the part of the root already found, viz., 2a 2 — 3ba. Divide the first term of the remainder by 12a 4 , and we obtain 6 2 for the last...

...is, three times the За + 36 part of the root already found. Moreover, we must add such a quantity to the second column as to obtain there three times...the square of the part of the root already found. ТЫя is conveniently effected thus: we have (За +6) 6 already in the second column (За + b) b,...

...is, three times the За + 36 part of the root already found. Moreover, we must add such a quantity to the second column as to obtain there three times the square of tJie part of the root already found. This is conveniently effected thus: we have ^ (За + 5) 51 already...

...must annex two ciphers, in order to increase their square an hundredfold. Thus finally we shall obtain three times the square of the part of the root already found. With these fresh numbers we continue the operation ••• before. L IL III. 150 •0001S5193 (•057...

...increased by the last term of the root, and subtract the product from Hie last remainder. 5Hi. Take three times the square of the part of the root already found for a new trial divisor, and proceed by division to find another term of the root. 6th. Complete the...

...for the first term of the root, and subtract its cube from the given quantity. (3) Take for divisor three times the square of the part of the root already found, divide this into the leading term of the remainder, and the quotient is the next term of the root....

...from the left-hand period, and to the remainder bring down the next period for a dividend. III. Take three times the square of the part of the root already found for a trial divisor. IV. Find how many times the trial divisor is contained in the dividend, exclusive...

...used, and with the remainder unite the next three terms of the given number for a dividend. 4. Take three times the square of the part of the root already found for a trial divisor, and by this divide the dividend (rejecting the lowest two terms of the dividend)...