 | George Anthony Hill - Geometry - 1880 - 332 pages
...positions shown in the figure. Corollaries. — I. By combining this theorem with § 128, we see that the area of a parallelogram is equal to the product of its base by its altitude. 2. All parallelograms having equal bases and equal altitudes are equivalent.... | |
 | George Albert Wentworth - 1881 - 266 pages
...; and the area of the figure equals 7X4. ! : i • Î : ! 1 ._ ! | ! PROPOSITION IV. THEOREM. 321. The area of a parallelogram is equal to the product of its base and altitude, BE С FB СE F D AD Let AE FD be a parallelogram, AD its base, and С D its altitude. We are to prove... | |
 | Education - 1890 - 384 pages
...x, equidistant from two given points, and also equidistant from two given parallel lines. 8. Prove: The area of a parallelogram is equal to the product of its base and altitude. 5). The base of a triangle is UK) varas .the altitude is 50 varas. What is its area. 10. The diameter... | |
 | F. B. Stevens - Examinations - 1884 - 202 pages
...a triangle divides the opposite side into segments whi^h are proportional to the adjacent sides. 3. The area of a parallelogram is equal to the product of its base and altitude. 4. How do you find the area of a trapezoid ? The areas of similar polygons are to each other in what... | |
 | Charles Davies, Adrien Marie Legendre - Geometry - 1885 - 538 pages
...lines, because the product is equal to the area of a rectangle constructed with the lines as sidea PROPOSITION V. THEOREM. The area of a parallelogram,...parallelogram, AB its base, and BE its altitude : then the area of ABCD is equal to AB x BE. For, construct the rectangle ABEF, having the same base and altitude... | |
 | Webster Wells - Geometry - 1886 - 392 pages
...square inches, and its base is 2 yards, what is its perimeter in feet? PROPOSITION IV. THEOREM. 324. The area of a parallelogram is equal to the product of its base and altitude. EBFC A b Let ABCD be a parallelogram having its altitude DF equal to a and its base AD equal to b.... | |
 | William Chauvenet, William Elwood Byerly - Geometry - 1887 - 331 pages
...PROPOSITION IV. The area of a rectangle is equal to the product of its base and altitude. PROPOSITION V. The area of a parallelogram is equal to the product of its base and altitude. PROPOSITION VI. The area of a triangle is equal to half the product of its base and altitude. Corollary... | |
 | William Chauvenet, William Elwood Byerly - Geometry - 1887 - 342 pages
...PROPOSITION-IV. The area of a rectangle is equal to the product of its base and altitude. PROPOSITION V. The area of a parallelogram is equal to the product of its base and altitude. PROPOSITION VI. The area of a triangle is equal to half the product of its base and altitude. Corollary... | |
 | Daniel Carhart - Surveying - 1888 - 528 pages
...is equal to the product of its length and breadth, or A = bl where b = breadth and I = length. 51. The Area of a Parallelogram is equal to the product of its base and altitude, or A = bh where b= breadth and h= height. 52. The Area of a Trapezoid is equal to the product of onehalf... | |
 | George Albert Wentworth - Geometry - 1888 - 272 pages
...the figure equals 7x4 units of surface. PLANE GEOMETRY. — BOOK IV. PROPOSITION IV. THEOREM. 365. The area of a parallelogram is equal to the product of its base and altitude. BECF A b DA 6 Z> Let AEFD be a parallelogram, AD its base, and CD its altitude. To prove the area of... | |
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The area of a parallelogram is equal to the product of its base and its height: A = bx h. 
