 | Elias Loomis - Geometry - 1871 - 302 pages
...linear units contained in the base, and the oth«r the number of linear units contained in the altitude. PROPOSITION V. THEOREM. The area of a parallelogram is equal to the product of its base by its altitude. Let ABCD be a parallelogram, AF its altitude, and AB its base ; then is its surface... | |
 | William Chauvenet - Mathematics - 1872 - 382 pages
...lines is measured by the product of the numerical measures of the lines. PROPOSITION IV.—THEOREM. 10. The area of a parallelogram is equal to the product...its base and altitude. Let ABCD be a parallelogram, k the numerical measure of its base AB, h that of its altitude AF; and denote its area by S; then,... | |
 | William Frothingham Bradbury - Geometry - 1872 - 262 pages
...be neglected. 9. CoroUary. The area of a square is the square of one of its sides. THEOREM III. 10, The area of a parallelogram is equal to the product of its base and altitude. Let DF be the altitude of the paral- E B_ FC lelogram A BCD; then the area of \l '. [~7 ABCD — ADXDF.... | |
 | William Frothingham Bradbury - Geometry - 1872 - 124 pages
...be neglected. 91 Corollary. The area of a square is the square of one of its sides. THEOREM III. 101 The area of a parallelogram is equal to the product of its base and altitude. Let DF be the altitude of the paral- E B_ _ F 0 lelogram ABCD ; then the area of / . \7 At A draw the perpendicular... | |
 | William Chauvenet - Geometry - 1872 - 382 pages
...of a number" has been adopted to signify "second power of a number." PROPOSITION IV.—THEOREM. 10. The area of a parallelogram is equal to the product of its base and altitude. Let And) be a parallelogram, k the numerical measure of its base AB, h that of its altitude AF; and denote... | |
 | Charles Davies - Geometry - 1872 - 464 pages
...continued product of the number of linear units in each of the three lines. Thus, when we say that the area of a parallelogram is equal to the product of its base and altitude, we mean that the number of superficial units in the parallelogram is equal to the number of linear... | |
 | William Frothingham Bradbury - Geometry - 1873 - 132 pages
...neglected. 9, Corollary. The area of a square is the square of one of its sides. THEOREM III. 10« The area of a parallelogram is equal to the product of its base and altitude. ' — 7 -- " - '• — 7 lelogram AB CD ; then the area of j / / Let DF be the altitude of the paral-... | |
 | Henry W. Jeans - 1873 - 272 pages
...4x57°-29577 57°-29577 5729577 whence BAC=53° 38' 30", and *=100 xtan. BAC=407'5. PEOB. 63. Since the area of a parallelogram is equal to the product of its base by its altitude,* and the area of triangle = J area of a parallelogram with same base and altitude,... | |
 | Henry William Jeans - 1873 - 292 pages
...57°.39577— 57°-29577 — 5729577" whence BAC=53° 38' 30", and a;=100xtan. BAC=407-5. PROB. 63. Since the area of a parallelogram is equal to the product of its base by its altitude,* and the area of triangle =£ area of a parallelogram with same base and altitude,... | |
 | Adrien Marie Legendre - Geometry - 1874 - 500 pages
...continued product of the number of linear units in each of the three lines. Thus, -when we say that the area of a parallelogram is equal to the product of its base and altitude, we mean that the number of superficial units in the parallelogram is equal to the number of linear... | |
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The area of a parallelogram is equal to the product of its base and its height: A = bx h. 
