 | Roswell Chamberlain Smith - Arithmetic - 1842 - 320 pages
...12. 31. Hence, when the extremes and common difference are given, to find the number of terms : — Divide the difference of the extremes by the common difference, and the quotient, increased by 1 , will be the answer. 32. If the extremes be 3 and 45, and the common difference 6,... | |
 | Nathan Daboll - Arithmetic - 1843 - 254 pages
...and the number of terms 140.) CASE IV. The first term, last term and common difference given, to jind the number of terms. RULE. Divide the difference of...extremes by the common difference, and the quotient increased by 1, will be the number of terms. EXAMPLES. 1. A man bought cloth in arithmetical progression,... | |
 | Nathan Daboll - 1843 - 260 pages
...and 912/. the u-hoU w. PROBLEM III. liivcR the first term, last term, and common difterenr.p to find the number of terms. RULE. Divide the difference of the extremes by the common ciifturerire, and the i|uotient increased by 1 is the nuinbei of terms. * EX AM PI. ES. I. f the extremes... | |
 | Roswell Chamberlain Smith - Arithmetic - 1843 - 320 pages
...31. Hence, when the extremes and common difference are given, to find the number of terms:—Divide the difference of the extremes by the common difference, and the quotient, increased by 1, will be the answer. 32. If the extremes be 3 and 45, and the common difference 6, what... | |
 | Charles Haynes Haswell - Engineering - 1844 - 298 pages
...in 12 hours ? 12X (134-2) =78 4«t. When the Common Difference and the Extremes are gieen, to find the Number of Terms. RULE.— Divide the difference of the extremes by the common difference, and add one to the quotient. EXAMPLE. — A man travelled 3 miles the first day, 5 the second, 7 the third,... | |
 | Benjamin Greenleaf - Arithmetic - 1844 - 352 pages
...basket ? Ans. 288090 miles, 2 rods. PROBLEM III. Given the extremes and the common difference, to find the number of terms. RULE. Divide the difference of the extremes by the common difference, and Ike quotient increased by one, will be the number of terms required 9. If the extremes are 3 and 45,... | |
 | Pliny Earle Chase - Arithmetic - 1844 - 246 pages
...5, gives 7, which must be equal to the number of terms less 1. Therefore the number of terms is 8. RULE. Divide the difference of the extremes by the common difference, and add 1 to the quotient. 13. What is the sum of the series 2, 4, 6, 8, &c., to 1000? 14. What is the... | |
 | Pliny Earle Chase - 1844 - 258 pages
...5, gives 7, which must be equal to the number of terms less 1. Therefore the number of terms is 8. RULE. Divide the difference of the extremes by the common difference, and add 1 to the quotient. 13. What is the sum of the series 2, 4, 6,8, &c., to 1000? 14. What is the sum... | |
 | Almon Ticknor - Arithmetic - 1846 - 274 pages
...will be doubled. Given the extremes and the common difference, to find the number of terms. RULE in. Divide the difference of the extremes by the common difference, and the quotient, increased by 1, will be the number of terms required. 5. The extremes are 3 and 39, and the common... | |
 | William Vogdes - Arithmetic - 1847 - 324 pages
...Washington ? § 166. CASE 3. Given the first term, the last term, and the common difference, to find the number of terms. RULE. Divide the difference of...extremes by the common difference, and the quotient increased by 1 is the number of terms required. EXAMPLES. 1. The extremes are 2 and 53, and the common... | |
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Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms. 
