 | Roswell Chamberlain Smith - Arithmetic - 1827 - 216 pages
...one to the basket ? A. 7042 miles. PROBLEM II. — Given the extremes and common difference to find the number of terms. RULE. — Divide the difference...extremes, by the common difference, and the quotient increased by 1, is the answer. EXAMPLES. — If the extremes be 3 and 45, and the common difference... | |
 | B. M. Tyler - Arithmetic - 1827 - 308 pages
...21 miles, and the last 70; — how many miles does he increase daily ? Ans. 7. PROBLEM IV. To find the number of terms. • RULE. Divide the difference of the extremes by the common difference, and add one to the quotient. Illustration. — The greatest term is made up of the common difference added... | |
 | Daniel Parker - Arithmetic - 1828 - 358 pages
...distance 455 miles. PROB. III. — Given the first term, last term, and common difference, to find the number of terms. RULE. Divide the difference of...extremes by the common difference, and the quotient increased by one, is the number of terms. Examples. 1. Let the extremes be 5 and 53, and the common... | |
 | Nathan Daboll - Arithmetic - 1828 - 268 pages
...and9lZl. the whole debt. PROBLEM III. Given the first term, last term, and common difference, to find the number of terms. RULE.' * Divide the difference of the extremes by the common difference, aml the quotient increased by 1 is the number of tanns. EXAMPLE8. 1. If the extremes be 3 and 45, and... | |
 | Nathan Daboll - Arithmetic - 1829 - 252 pages
...and 9121. the whole debt. PROBLEM HI. Given the first term, last term, and common difference, to find the number of terms. RULE. — Divide the difference...extremes by the common difference, and the quotient increased by 1 is the number of terms. EXAMPLES. 1. If the extremes be 3 and 45, and the common difference... | |
 | William Kinne - 1829 - 246 pages
...Ans. 4 years. PROBLEM 111. Given the first term, the last term, and the common difference, to find the number of terms. RULE. — Divide the difference...extremes by the common difference, and the quotient increased by 1, is the number of terms required. EXAMPLES. 1. The extremes are 3 and 19, and the common... | |
 | Nathan Daboll - Arithmetic - 1829 - 268 pages
...thewhol* debt. PROBLEM III Given the first term, last term, and common difference, to find the numbei of terms RULE. Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number o» terms EXAMPLES. 1. If the extremes be 3 and 45, and the coamon difference... | |
 | Roswell Chamberlain Smith - Arithmetic - 1830 - 286 pages
...A. l2. Hence, when the extremes aiid common difference are given, to find the number of terms ; — Divide the difference of the extremes by the common difference, and the quotient, increased by 1, will If e the answer. 17. If the extremes be 3 and 45j and the common difference 6,... | |
 | Ira Wanzer - Arithmetic - 1831 - 408 pages
...Prub. II. PROBLEM IV. — The extremes and the common difference of the terms being given, to find the number of terms. RULE.— Divide the difference of the extremes by the common difference of the terms, and the quotient, increased by 1, will be the answer. "„ Ex. 1. If the extremes be... | |
 | Roswell Chamberlain Smith - Arithmetic - 1831 - 286 pages
...terms. A. 32. Hence, when the extremes and common difference are given, to und the number of terms ; — Divide the difference of the extremes by the common difference^. and the quotiejil, increased by 1, will be the answer. 17. If the extremes bo 3 and 45, aud the common ilifloronce... | |
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Divide the difference of the extremes by the common difference, and the quotient increased by 1 is the number of terms. 
