Divide the first term of the remainder by three times the square of the first term of the root, and write the result as the next term of the root. Intermediate Algebra - Page 127by Herbert Ellsworth Slaught, Nels Johann Lennes - 1916 - 256 pagesFull view - About this book
| Fletcher Durell, Edward Rutledge Robbins - Algebra - 1897 - 482 pages
...term of the cube expression, 8c№, and may be obtained from it by dividing it by За2 ; that is, by three times the square of the first term of the root (called the trial divisor). If we take the trial divisor, and add to it three times the product of... | |
| Webster Wells - Algebra - 1897 - 426 pages
...aЬ2 + b3, or (3 a- + .'! <Л + h*)b. If we divide the first term of this remainder by 3 а2, that is, by three times the square of the first term of the root, we obtain the second term of the root, Ь. Adding to the trial-divisor 3 ab, that is, three times the... | |
| George Egbert Fisher, Isaac Joachim Schwatt - Algebra - 1898 - 714 pages
...have been found, obtain each succeeding term by dividing the first term of the remainder at that stage by three times the square of the first term of the root. Find the next remainder by subtracting from the last remainder the expression wherein a stands for... | |
| George Egbert Fisher, Isaac Joachim Schwatt - Algebra - 1900 - 512 pages
...have been found, obtain each succeeding term by dividing the first term of the remainder at that stage by three times the square of the first term of the root. Find the next remainder by subtracting from the last remainder the expression (За2 + За& + b^)b,... | |
| George Egbert Fisher, Isaac Joachim Schwatt - Algebra - 1900 - 206 pages
...have been found, obtain each succeeding term by dividing the first term of the remainder at that stage by three times the square of the first term of the root. Find the next remainder by subtracting from the last remainder the expression (3 a2 + 3 a6 + b2) b,... | |
| James Morford Taylor - Algebra - 1900 - 504 pages
...two or more terms, is subtracted from the radicand, and the first term of the remainder is divided by three times the square of the first term of the root, the quotient will be the next term of the root. Eg, by (i), the first term of the cube root of is v/8zs,... | |
| James Harrington Boyd - Algebra - 1901 - 818 pages
...second term b of the root ia found by dividing 3a*i>, the first term in the remainder, by 3 a*; ie , by three times the square of the first term of the root, a. Since the remainder 3 a»6 + 3 a¿.3 + Is = Ь (3 ч- + 3 ai + ¿>2), the complete trial divisor... | |
| George Egbert Fisher - 1901 - 622 pages
...have been found, obtain each succeeding term by dividing the first term of the remainder at that stage by three times the square of the first term of the root. Find the next remainder by subtracting from the last remainder the expression (3 a2 + 3 ab + ö2) b,... | |
| James Harrington Boyd - Algebra - 1901 - 812 pages
...second term b of the root is found by dividing 3 <rb, the first term in the remainder, by За1; ie , by three times the square of the first term of the root, n. Since the remainder 3 аг& + 3 ab2 + l3 = Ь (3 аг + 3 ab + //-), the complete trial divisor... | |
| George Egbert Fisher, Isaac Joachim Schwatt - Algebra - 1901 - 664 pages
...have been found, obtain each succeeding term by dividing the first term of the remainder at that stage by three times the square of the first term of the root. Find the next remainder by subtracting from the last remainder the expression (3 a2 + 3 ao + b2) ft,... | |
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