Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend. Elements of Geometry - Page 44by Adrien Marie Legendre - 1825 - 224 pagesFull view - About this book
| Horatio Nelson Robinson - Arithmetic - 1860 - 444 pages
...hand of the dividend, as in simple, numbers II. Find the first term of the quotient either by dividing **the first term of the dividend by the first term of the divisor,** or by dividing the first two terms of the dividend by the first two terms of the divisor ; multiply... | |
| Robert Fowler - 1861
...both the divisor and dividend according to the powers of the same letter (a in the example) ; then to **divide the first term of the dividend by the first term of the divisor,** place the result in the quotient and multiply the divisor by it ; subtract and proceed similarly with... | |
| Thomas Sherwin - 1862 - 252 pages
...before; and thus continue, until all the terms of the root are found. \ Remark 2. In dividing, we merely **divide the first term of the dividend by the first term of the divisor; and** it is manifest, from the manner in which the divisors are obtained, as well as from inspection, that... | |
| Isaac Todhunter - Algebra - 1863 - 264 pages
...ascending powers of some common letter, or both according to descending powers of some common letter. **Divide the first term of the dividend by the first term of the divisor, and** put the result for the first term of the quotient; multiply the whole divisor by this term and subtract... | |
| Horatio Nelson Robinson - Algebra - 1863 - 432 pages
...quotient similarly arranged. We can therefore obtain this term of the quotient, by simply dividing **the first term of the dividend by the first term of the divisor,** thus arranged. The operation may then be continued in the manner of long division in Arithmetic ; each... | |
| Benjamin Greenleaf - 1863 - 338 pages
...terms, 3а? с -\-6abc -f- 3 V с -{- 3 a c1.-f- 3 6 c1 -f- c", for a remainder or dividend. Dividing **the first term of the dividend by the first term of the** trial divisor, 3а1, we obtain c, the third term of the root. Adding together three times the square... | |
| Benjamin Greenleaf - Algebra - 1864 - 420 pages
...Hence, the RULE. Arrange loth dividend and divisor according to the decreasing powers of some letter. **Divide the first term of the dividend by the first term of the divisor, and write the result** for the first term of the quotient. Multiply the whole divisor by this term, and subtract the product... | |
| Elias Loomis - Algebra - 1864 - 386 pages
...divisor. (74.) From this investigation we deduce the following BULK FOR THE DIVISION OF POLYNOMIALS. 2. **Divide the first term of the dividend by the first term of the divisor,** the result will be the first term of the quotient. 3. Multiply the divisor by this term, and subtract... | |
| Horatio Nelson Robinson - Algebra - 1864 - 444 pages
...quotient similarly arranged. We can therefore obtain this term of the quotient, by simply dividing **the first term of the dividend by the first term of the divisor,** thus arranged. The operation may then be continued in the manner of long division in Arithmetic; each... | |
| Joseph Ray - Algebra - 1852 - 396 pages
...and divisor with reference to a certain letter, and place the divisor on the right of the dividend. **Divide the first term of the dividend by the first term of the divisor** ; the result will be the first term of the quotient. Multiply the divisor ty this term, and subtract... | |
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