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" The area of a triangle is equal to half the product of the base and height. "
Elements of Drawing and Mensuration Applied to the Mechanic Arts: A Book for ... - Page 111
by Charles Davies - 1846 - 240 pages
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Appleton's New Practical Cyclopedia: A New Work of Reference Based ..., Volume 4

Marcus Benjamin, Arthur Elmore Bostwick, Gerald Van Casteel, George Jotham Hagar - Encyclopedias - 1910 - 538 pages
...to the product of these numbers expressed in terms of a square inch or square foot, etc. Again, the area of a triangle is equal to half the product of the base into the height. From this we can derive the area of any plane figure bounded by right lines, as such...
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Special Reports on Educational Subjects, Volumes 26-27

Great Britain. Board of Education - Education - 1912 - 1044 pages
...as a rectangle and having the same altitude has half the area of the rectangle, it follows that the area of a triangle is equal to half the product of the base and altitude. Hence the truth of the first proposition of Euclid's sixth book follows at once. Consider...
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School Algebra: First Course

Henry Lewis Rietz, Arthur Robert Crathorne, Edson Homer Taylor - Algebra - 1915 - 302 pages
...the two fractions this rule becomes . 6. Area of a triangle. In arithmetic it was learned that the area of a triangle is equal to half the product of the base and altitude. In symbols i bh A = Tf where A is the area, b the base, and h the altitude. 7. Circumference...
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School Algebra: First-[second], Book 1

Henry Lewis Rietz, Arthur Robert Orathorne, Edson Homer Taylor - Algebra - 1915 - 300 pages
...two fractions this rule becomes (Í С 6. Area of a triangle. In arithmetic it was learned that the area of a triangle is equal to half the product of the base and altitude. In symbols A = —, where A is the area, b the base, and h the altitude. 7. Circumference...
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Junior High School Mathematics, Book 1

George Wentworth, David Eugene Smith, Joseph Clifton Brown - Mathematics - 1917 - 264 pages
...Triangle. From the illustrations given and the questions asked on page 169 it is easily seen that The area of a triangle is equal to half the product of the base and height. This may be expressed by the formula A = % bh. For example, what is the area of a triangle...
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Hopkins and Underwood's Arithmetic, Book 2

John William Hopkins - Arithmetic - 1918 - 392 pages
...triangles are equal. Therefore, the triangle ABC is equal to half of the parallelogram ABCD. Therefore, the area of the triangle ABC is equal to half the product of AC by BH. The area of a triangle is equal to half the product of its base by its altitude. Thus, the...
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School Arithmetics: Book One-three, Book 3

George Albert Wentworth, David Eugene Smith - Arithmetic - 1920 - 380 pages
...For example, if the base is 2.4 in. and the height 2 in., we have 2 x 2.4 sq. in. = 4.8 sq. in. The area of a triangle is equal to half the product of the base and the height. For example, if the base is 3J in. and the height 2 J in., we have ^ of 2J x 3^ sq....
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Elementary Experimental Science: Physics

W. T. Clough - Chemistry - 1923 - 294 pages
...the two triangles ABC and BCD arc equal. But the area of the parallelogram is equal to AB x CE. Hence the area of the triangle ABC is equal to half the product of AB and CE, that is, half the base multiplied by the perpendicular height. Cut out the triangle BCD, and...
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Engineering Technology Problem Solving: Techniques Using Electronic ...

H. Irvine - Technology & Engineering - 1992 - 292 pages
...CIRCUMSCRIBED CIRCLE r IS RADIUS OF INSCRIBED CIRCLE FIG. 2.3 Areas of plane straight-sided figures. of a triangle is equal to half the product of the base and the height regardless of whether it is a right or oblique triangle. Also note that the area of...
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Mesuration and Elementary Solid Geometry for Schools

228 pages
...equations for case (a) and subtracting for case (b) we have A ABC = J rectangle BCNM = | base x height. The area of a triangle is equal to half the product of the base and the height. 16. If we denote the sides of the triangle ABC by a, b and c and the angles by A, B...
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