 | Algebra - 1847 - 408 pages
...the quotient; muliply the divisor by this term and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, for the second term of the quotient; multiply the divisor by this second term, and subtract... | |
 | George Roberts Perkins - Algebra - 1848 - 234 pages
...term of the root sought. II. Subtract the power of this first term of the root from the polynomial, and divide the first term of the remainder, by the first term of the root involved to the next inferior power, and multiplied by the number denoting the root ; the quotient... | |
 | Joseph Ray - Algebra - 1848 - 250 pages
...product from the remainder. 3d. Double the terms of the root already found, for a partial divvsor, and divide the first term of the remainder, by the first term of the divisor, and annex the result both to the root and the partial dieisor. Multiply the divisor thus increased,... | |
 | Jeremiah Day, James Bates Thomson - Algebra - 1848 - 264 pages
...first term, for the first term of the required root. III. Subtract the power from the given quantity, and divide the first term of the remainder by the first term of the root inrolved io the next inferior power and multiplied by the index of the given power ;* the quotient... | |
 | Samuel Alsop - Algebra - 1848 - 336 pages
...thus determined, and mblract the product from the dividend, arranging the terms as above directed. Divide the first term of the remainder by the first term of the divisor, and so proceed until the operation is accomplished. EXAMPLES. Ex. 1. a — x) a? — 2 ax... | |
 | Joseph Ray - Algebra - 1848 - 252 pages
...term of the quotient. Multiply the divisor by this term, and subtract the product from the dividend. Divide the first term of the remainder by the first term of the divisor, the result will be the second term of the quotient. Multiply the divisor by this term, and... | |
 | Charles Davies - Algebra - 1848 - 302 pages
...quotient ; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives the second term of the quotient ; multiply the divisor by the second term, and... | |
 | Stephen Chase - Algebra - 1849 - 348 pages
...subtract its square from the given polynomial. 3. Double the part of the root already found, for a partial divisor ; and divide the first term of the remainder by the first term of the doubled root; setting the quotient, with its proper sign, as a term both of the root and of the divisor.... | |
 | George Roberts Perkins - Algebra - 1850 - 276 pages
...the quotient; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives the second term of the quotient; multiply the divisor by this second term; and... | |
 | William Smyth - Algebra - 1851 - 272 pages
...Multiply the divisor by this first term of the quotient and subtract the product from the dividend. 3°. Divide the first term of the remainder by the first term of the divisor, place the result in the quotient with its proper sign, multiply and subtract as before, and... | |
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Then divide the first term of the remainder by the first term of the divisor... 
