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" In each succeeding term the coefficient is found by multiplying the coefficient of the preceding term by the exponent of a in that term, and dividing by the number of the preceding term. "
Elementary Algebra: Second Year Course - Page 65
by Florian Cajori - 1916
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Advanced Algebra for Colleges and Schools

William James Milne - Algebra - 1902 - 620 pages
...second term is the same as the index of the required power. ñ. The coefficient of any term may be found by multiplying the coefficient of the preceding term by the exponent of the first term of the binomial found in that term, and then dividing the i-esult by t It inumber of...
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High School Algebra

Middlesex Alfred Bailey - Algebra - 1902 - 336 pages
...second term is the same as the exponent of the binomial; the coefficient of each succeeding term may be found by multiplying the coefficient of the preceding term by the exponent of the leading letter, and dividing by the exponent of the second letter increased by one. If the second...
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An Algebra for High Schools and Academies

Louis Parker Jocelyn - Algebra - 1902 - 460 pages
...of the second, the exponent of the binomial. 2. The coefficient of any term after the first may be found by multiplying the coefficient of the preceding term by the exponent of the letter of arrangement in that term, and dividing the product by the number of terms thus far obtained....
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Academic Algebra

Wooster Woodruff Beman, David Eugene Smith - Algebra - 1902 - 410 pages
...1 from 0 £on ; 3. ÎVie Jíreí coefficient is 1, í/te second is n, <md anу oí/2er í's formed by multiplying the coefficient of the preceding term by the exponent, of a ¡n í/гaí íerí/i and dividing by 1 more i/ian the exponent of b. ILLUSTRATIVE PROBLEMS 1. Expand...
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School Algebra

John Marvin Colaw - Algebra - 1903 - 444 pages
...coefficient is 1 , the S3cond is equal to the binomial exponent; and the coefficient of any succeeding term is found by multiplying the coefficient of the preceding...term, and dividing by 1 more than the exponent of 6. The student should carefully review Art. 119. 1. Kaise (2 x — 3 y) to the 3d power. (2 x - 3 y)3...
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Standard Algebra

William James Milne - Algebra - 1908 - 476 pages
...the xewnd term is the same as the index of the required power. 6. The coefficient of any term may be found by multiplying the coefficient of the preceding...term by the exponent of a in that term, and dividing this product by the number of the term. Ï. All the terms are positive, if both terms of the binomial...
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High School Algebra: Advanced Course

Herbert Ellsworth Slaught, Nels Johann Lennes - Algebra - 1908 - 216 pages
...binomial ; and the coefficient of any other term may be found by multiplying the coefficient of the next preceding term by the exponent of a in that term and dividing this product by a number one greater than the exponent of b in that term. 5. The coefficients of any...
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High School Algebra: Complete Course

Herbert Ellsworth Slaught, Nels Johann Lennes - Algebra - 1908 - 520 pages
...binomial ; and the coefficient of any other term may be found by multiplying the coefficient of the next preceding term by the exponent of a in that term and dividing this product by a number one greater than the exponent of 6 in that term. 5. The coefficients of any...
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A Grammar School Algebra

Fletcher Durell, Edward Rutledge Robbins - Algebra - 1909 - 296 pages
...; of the second term it is the index of the required power. In each succeeding term the coefficient is found by multiplying the coefficient of the preceding...by the exponent of a in that term, and dividing by the exponent of Ь increased by 1. IV. Signs of Terms. If the binomial is a difference, the signs of...
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First Year Algebra

William James Milne - Algebra - 1911 - 332 pages
...the second term is the same as the index of the required power. 6. The coefficient of any term may be found by multiplying the coefficient of the preceding...term by the exponent of a in that term, and dividing this product by the number of the term. 7. All the terms are positive, if both terms of the binomial...
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