 | Edward Olney - Algebra - 1881 - 504 pages
...write it as the laghcst order in the root. Subtract the square of this figure from the period used, and to the remainder annex the next period for a new dividend. III. Double the root already found for a Trial Divisor, by which divide the new dividend, rejecting... | |
 | Alexander Ingram - 1883 - 190 pages
...multiply the divisor thus comEVOLUTION. pleted by this figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 4. Add the last figure of the root to the last complete divisor for a new partial divisor, and proceed... | |
 | James William Nicholson - Arithmetic - 1885 - 348 pages
...rootfigure. Multiply the true divisor by the last root-figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. Proceed with the second, and each succeeding dividend, in the same manner as with the first, until... | |
 | Christian Brothers - Arithmetic - 1888 - 484 pages
...Multiply the COMPLETE DIVISOR by the last term of the root, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. VI. Follow the same method until all the periods have been used. NOTE. — If a cipher occur in the... | |
 | Edward Brooks - Algebra - 1888 - 344 pages
...Multiply the COMPLETE DIVISOR by the last term of the root; subtract the product from the dividend, and to the remainder annex the next period for a new dividend. Take 3 time» the square of the root now found, regarded as tens, for a trial divisor, and find the... | |
 | James William Nicholson - Arithmetic - 1889 - 408 pages
...root-figure. IV. Multiply the true divisor by the last root-figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. V. Proceed with the second, and each succeeding dividend, in the same manner as with the first, until... | |
 | William Frothingham Bradbury, Grenville C. Emery - Algebra - 1889 - 428 pages
...DIVISOR. Multiply the tne divisor by this new root fiyure, subtract the product from tlu dividend, and to the remainder annex the next period, for a new dividend. Double the part of the root already found for a trial divisor, and proceed as before, until all tk... | |
 | John Groesbeck - 1891 - 426 pages
...Multiply the complete divisor by the last figure of the root; subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 6. Proceed in the same manner with all the periods to the last. The result will be the square root... | |
 | William Frothingham Bradbury - Arithmetic - 1895 - 398 pages
...divisor. 5. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 6. Find a new trial divisor, and proceed as before, until all the periods have bееп employed. NOTE.... | |
 | William Seneca Sutton - 1896 - 342 pages
...root-figure. (v) Multiply the true divisor by the last root-figure; subtract the product from the dividend, and to the remainder annex the next period for a new dividend. (vi) Square the sum of the first root-figure considered as hundreds and the second root-figure considered... | |
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Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 
