 | William Templeton (engineer.) - 1833 - 224 pages
...period ; then from the first period subtract the greatest cube it contains ; put the root as a quotient, and to the remainder bring down the next period for a dividend. Find a divisor by multiplying the square of the root by 300 ; see how often it is contained in the... | |
 | Frederick Emerson - Arithmetic - 1834 - 300 pages
...period, and write its root in the quotient. Subtract the square of this root from the left hand period, and to the remainder bring- down the next period for a dividend. Thirdly — Double the root already found, for a divisor. Ascertain how many times the divisor is contained... | |
 | Benjamin Snowden - 1835 - 108 pages
...its root for the first figure of the root sought. 2. — Subtract this cube from the first period, and to the remainder bring down the next period for a dividend. 3. — Find a divisor by multiplying the square of the root by 300. 4. — Divide the dividend by this... | |
 | George Willson - Arithmetic - 1836 - 202 pages
...hand of the given number for the first figure of the root, and the square itself under the period, and subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Double the root already found, and annex a cipher to tho product, for a divisior. Seek how many... | |
 | Mathematics - 1836 - 488 pages
...subtract from the highest period the greatest square contained in it, place the root in the quotient, and to the remainder bring down the next period for a dividend. 2. Double the root already found, (understanding a cypher at the right,) for a divisor, and divide... | |
 | Silas Totten - Algebra - 1836 - 332 pages
...right, after the manner of a quotient in division. Subtract its cube from the aforementioned period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by 300, for a divisor. Seek how often the divisor is... | |
 | Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...and place it as a quotient in division. Place the square of the root found, under said period, and subtract it therefrom, and to the remainder bring down the next period for a dividend. III. Double the root already found, for a divisor ; see how often the divisor is contained in the dividend,... | |
 | Benjamin Greenleaf - Arithmetic - 1839 - 356 pages
...quotient in division,} for the first figure of the root, and the square number under the period, and subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek... | |
 | Nathan Daboll - 1839 - 220 pages
...6 7 8 9 SQUARES. ' 1 J4|. 9 16 | 25 36 49 64 81 CUBES. | 1 | 8 | 27 | 64 | 125 218 | 343 512 | 729 subtract it therefrom, and to the remainder bring down the next period for a new dividend. 6. Double the figures already found in the root for a new divisor ; and from these find... | |
 | Daniel Adams - 1839 - 268 pages
...and write its root as a quotient in division. Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how iiany times the divisor is contained in... | |
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... it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained... 
