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" From eight times the chord of half the arc, subtract the chord of the whole arc, and divide the remainder by 3, and the quotient will be the length of the arc, nearly. "
Ticknor's Mensuration, Or, Square and Triangle: Being a Practical and ... - Page 68
by Almon Ticknor - 1849 - 144 pages
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Mensuration for pupil teachers

James Elliot - Measurement - 1879 - 118 pages
...a quadrant. PROBLEM XIII. To find the Length of an Arc (BCE) approximately (without Tables). RULE. From eight times the chord of half the arc subtract...chord of the whole arc, and divide the remainder by 3. FORMULA. Arc = • + t. \ 3 \ c being the chord of the whole * arc, and d that of half the arc....
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Moffatt's pupil teachers' course (ed. by T. Page). Candidates, 2nd (-4th) year

Moffatt and Paige - 1879 - 506 pages
...of half the arc, the length of the arc may be found by the following rule (proved by Trigonometry). From eight times the chord of half the arc, subtract the chord of the whole arc, and take one-third of the remainder for the length of the arc nearly. (12) Find the ratio of the area of...
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The naval architect's and shipbuilder's pocket book of formulæ [&c.].

Clement Mackrow - 1879 - 552 pages
...6-18182 7-69421 9-36564 11-19615 8. To find the length of any are of a circle. (Fig. 73.) RULE (I.) — From eight times the chord of half the arc subtract the chord of the whole arc; one-third of the remainder will be the length of the arc, nearly. Thus if L = length of the arc, C...
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Explanatory Mensuration

Alfred Hiley - 1879 - 228 pages
...circle less than a semicircle, when the chord of the arc and the chord of half the arc are given. From 8 times the chord of half the arc subtract the chord of the whole arc ; divide the remainder by 3, and the quotient is the length of the arc, nearly. Note'].. — The answers...
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The engineers' manual of the Local marine examinations

Thomas Liddell Ainsley - 1880 - 866 pages
...circle bounded by an arc and two radii. 221. To find the length of an arc. EULE LXX. From eight time» the chord of half the arc subtract the chord of the whole are, and take one-third the remainder for the length of the arc, nearly. 222. To find the area of the...
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Manual of Mensuration: For Common and High Schools

Henry H. Hutton - Measurement - 1882 - 178 pages
...radius 18.75. EXERCISE xv. of the whole arc 38 feet; what is the length of the arc ? Special Rule. From eight times the chord of half the arc subtract the chord of the whole arc; one-third of the remainder will give the arc, nearly. %. The chord of an arc is 6 feet and the chord...
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Practical Mechanics

John Perry - Machinery, Kinematics of - 1883 - 486 pages
...together. Fig 146 Circumference of a circle. — Multiply the diameter by 3 -1416. Arc of a circle. — From eight times the chord of half the arc subtract the chord of the whole arc, one-third of the remainder will give the length of the arc, nearly. Area of circle. — Square the...
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Calendar of Dalhousie College and University

Dalhousie University - 1886 - 216 pages
...m6=x—x. ' x * 4. Prove the rough rule for finding the length of a small arc of a circle, "From 8 times the chord of half the arc, subtract the chord of the whole arc, and take Jrd of the remainder." (Euler's series for the sine. ) 5. Express sin " "*" 0 in terms of descending...
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A Mathematical Solution Book Containing Systematic Solutions to Many of the ...

Benjamin Franklin Finkel - Mathematics - 1888 - 518 pages
...s=arc=$(8t> — «)*, where a is the chord of the whole arc and b the chord of half the arc. Rule from (6) . From eight times the chord of half the arc subtract the chord of the whole arc ; one-third of the remainder will be the length of the arc, approximately. I. Find the length of the...
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English Mechanic and World of Science: With which are ..., Volume 13

Industrial arts - 1871 - 682 pages
...to give H, &c., for Hydrogen &c — r. HWB [7008.]— Mensuration— Segment of Circle.— l;>'l" : From eight times the chord of half the arc subtract the chord of the whole arc : one third of the remainder is the length of the arc nearly. Note : When, us in this case, the segment...
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