 | Charles Davies - Algebra - 1845 - 382 pages
...dividend by the first term on the left of the divisor, for thn first term of the quotient; muliply the divisor by this term and subtract the product...Then divide the first term of the remainder by the Jirst term of the divisor, for the second term of the quotient ; multiply the divisor by this second... | |
 | Harvey Goodwin - Mathematics - 1846 - 500 pages
...common to the two; the division of the first term of the dividend by the first term of the divisor gives the first term of the quotient ; multiply the divisor...this term, and subtract the product from the dividend ; bring down as many more of the terms of the dividend as may be required, and repeat the process until... | |
 | Elias Loomis - Algebra - 1846 - 376 pages
...remainder by t he first term of the divisor, the result will be the second term of the quotient. 5. Multiply the divisor by this term, and subtract the product from the last remainder. Continue the same operation, and if you obtain 0 for a remainder, the division is said... | |
 | Elias Loomis - Algebra - 1846 - 380 pages
...remainder by the first term of the divisor, the result will be the second term of the quotient. 5. Multiply the divisor by this term, and subtract the product from the last remainder. Continue the same operation, and if you obtain 0 for a remainder, the division is said... | |
 | Davis Wasgatt Clark - Algebra - 1846 - 374 pages
...exponents shall diminish from left to right. 2. Divide the first term of the dividend by the first term of the divisor ; the result is the first term of the quotient. 3. Multiply the-whole divisor by this term, and subtract the product from the dividend ; the remainder... | |
 | Algebra - 1847 - 386 pages
...dividend by the first term on the left of the divisor, for the ßrst term of the quotient; muliply the divisor by this term and subtract the product from the dividend. II. Then divide the ßrst term of the remainder by the ßrst term of the divisor, for the second term of the quotient ;... | |
 | George Roberts Perkins - Algebra - 1848 - 234 pages
...term on the left of the dividend by the first term, on the left of the divisor, the result is the fast term of the quotient; multiply the divisor by this...the product from the dividend. \ II. Then divide the fast term of the remainder by the fast term of the divisor, which gives the second term of the quotient;... | |
 | Joseph Ray - Algebra - 1848 - 252 pages
...ANOTHER. Divide tlie first term of the dividend by the first term of the divisor, the result will be the first term of the quotient. Multiply the divisor...term, and subtract the product from the dividend. Divide the first term of the remainder by the first term of the divisor, the result will be the second... | |
 | Joseph Ray - Algebra - 1848 - 250 pages
...Divide the first term of the remainder by the first term of the divisor, the result will be the second term of the quotient. Multiply the divisor by this term, and subtract the product from the last remainder. Proceed in the same manner, and if you obtain 0 for a remainder, the division is said... | |
 | Charles Davies - Algebra - 1851 - 300 pages
...reference to a certain letter, and then divide the first term on the left of the dividend by the first term on the left of the divisor, the result is the...divisor by this term, and subtract the product from tJte dividend. II. Then divide the first term of the remainder by the first term of the divisor, which... | |
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... the first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend. 
