 | Benjamin Greenleaf - Geometry - 1863 - 504 pages
...solid contents of the cylinder will bo represented by R2 X i X H. PROPOSITION III. — THEOREM. 579. The convex surface of a cone is equal to the circumference of the base multiplied by half the slant height. Let ABCDEF - S be a cone S whose base is the circle ABCDEF, and whose slant height... | |
 | Woolwich roy. military acad - 1864 - 588 pages
...SY the perpendicular from S on the tangent to the curve at P. f 6. Prove that the surface of a right cone is equal to the circumference of the base multiplied by half the slant side. MIXED MATHEMATICS. REV. CANON HEAVISIDE, MA 1. Forces 1, 4, 8, not in one plane act... | |
 | Benjamin Greenleaf - Geometry - 1868 - 340 pages
...solid contents of the cylinder will be represented by K2 X « X H. PROPOSITION III. — THEOREM. 579. The convex surface of a cone is equal to the circumference of the base multiplied by half the slant height. Let ABCDEF - S be a cone whose base is the circle ABCDEF, and whose slant height... | |
 | Edward Brooks - Geometry - 1868 - 284 pages
...as the cubes of their altitudes, or of the radii of the bases. Let the pupil prove it. THEOREM in. The convex surface of a cone is equal to the circumference of its base multiplied by one-half of the slant height. circumference of its base multiplied by one-half... | |
 | Charles Davies - Geometry - 1872 - 464 pages
...altitudes, or the cylinders themselves, are as the cubes of the altitudes. PROPOSITION III. THEOREM. The convex surface of a cone is equal to the circumference of its base multiplied by half the slant height. Let S-ACD be a cone whose base is ACD, and whose slant... | |
 | Benjamin Greenleaf - Geometry - 1873 - 202 pages
...2, Bk. IV.), the solid contents of the cylinder will be represented by R* X - X H. THEOREM III. 345. The convex surface of a cone is equal to the circumference of the base multiplied by half the slant hight. Let ABC DE FS be a cone whose base is the circle ABCDEF, and whose slant hight is... | |
 | Gerardus Beekman Docharty - Calculus - 1865 - 328 pages
...But \ \/a:2+y2=half the slant height of the cone, and 2<7r!/= circumference of the base. Therefore the convex surface of a cone is equal to the circumference of the base multiplied by half the slant height. Cor. Taking the limits between x and x+h, we shall have the convex surface of the... | |
 | David Munn - 1873 - 160 pages
...the perimeter of the base by one-half the slant height 63 VL The lateral surface of a right circular cone is equal to the circumference of the base multiplied by half the slant height 64 VII. Lemma. The surface generated by a straight line revolving about an axis in... | |
 | Benjamin Greenleaf - Geometry - 1874 - 206 pages
...2, Bk. IV.), the solid contents of the cylinder will be represented by Ra X - X H. THEOREM III. 345. The convex surface of a cone is equal to the circumference of the base multiplied by half the slant hight. Let ABCDE FS be a cone whose base is the circle ABCDEF, and whose slant hight is the... | |
 | Adrien Marie Legendre - Geometry - 1874 - 500 pages
...altitudes, or the cylinders themselves, are as the cubes of the altitudes. PROPOSITION III. THEOREM. The convex surface of a cone is equal to the circumference of its base multiplied by half the slant height. Let S-ACD be a cone whose base is ACD, and whose slant... | |
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The convex surface of a cone is equal to the circumference of the base multiplied by half the slant height. 
