 | Nathan Scholfield - 1845 - 894 pages
...surface of the pyramid is equal to the perimeter of the base, multiplied by half the slant height : hence the convex surface of a cone is equal to the circumference of the base, multiplied by half the side. Scholium. Let L be the side of a cone, R the radius of its base ; the circumference of this... | |
 | Charles Davies - Geometrical drawing - 1846 - 254 pages
...away, the remaining part is called the frustum of a cone. 38. How do you find the surface of a cone ? The convex surface of a cone is equal to the circumference of the base multiplied by half the slant height. Thus, the convex surface of the cone C — AED is equal to circumference AED x 3... | |
 | George Roberts Perkins - Geometry - 1847 - 326 pages
...multiplied by half the side cannot be the measure of the surface of a smaller cone. Therefore, finally, the convex surface of a cone is equal to the circumference of its base multiplied by half its side. Schol. Let L be the side of a cone, R the radius of its base... | |
 | Charles Davies - Trigonometry - 1849 - 372 pages
...altitudes, or the cylinders themselves, are as the cube,s of the altitudes. PROPOSITION III. THEOREM. The convex surface of a cone is equal to the circumference of its base, multiplied by half its side. Let the circle ABCD be the base of a cone, S the vertex, SO... | |
 | George Roberts Perkins - Geometry - 1850 - 332 pages
...H its altitude; the solidity of the cone will be * R" x i H, or i -r R'H. PROPOSITION VI. THEOREM. The convex surface of a cone is equal to the circumference of its base multiplied by half its side. Let AO be a radius of the base of the given cone, S its vertex,... | |
 | Elias Loomis - Calculus - 1851 - 300 pages
...a:=AB=A, we have the surface of the cone whose altitude is A, and the radius of its base b, AC that is, the convex surface of a cone is equal to the circumference of its base into half its side. Ex. 2. It is required to determine the convex surface of a cylinder. If... | |
 | Adrien Marie Legendre - Geometry - 1852 - 436 pages
...radius of a cjdinder's base, and H the altitude ; then we shall have, R 208 PBOPOSITION III. THEOEEM. The convex surface of a cone is equal to the circumference of its base, multiplied by half the slant height. Let the circle ABCD be the base of a cone; S the vertex,... | |
 | Charles Davies - Geometry - 1854 - 436 pages
...of base=*XR , convex surface=2*XJZ2 XH, solidity =* X Rx H. 208 GEOMETRY. PROPOSITION ln. THEOREM. The convex surface of a cone is equal to the circumference of its base, multiplied by half the slant height. Let the circle ABCD be the base of a cone, S the vertex,... | |
 | Benjamin Greenleaf - Geometry - 1862 - 518 pages
...solid contents of the cylinder will be represented by R2 XTX H. PROPOSITION III. — THEOREM. 579. The convex surface of a cone is equal to the circumference of the base multiplied by half the slant height. Let ABCDE FS be a cone whose base is the circle ABCDEF, and whose slant height is... | |
 | Benjamin Greenleaf - Geometry - 1861 - 638 pages
...cylinder will be represented by Ra X n X H. ELEMENTS OP GEOMETRY. PROPOSITION III. — THEOREM. 579. The convex surface of a cone is equal to the circumference of the base multiplied by half the slant height. Let ABCDE FS be a cone S whose base is the circle ABCDEF, and whose slant height... | |
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The convex surface of a cone is equal to the circumference of the base multiplied by half the slant height. 
