 | George Roberts Perkins - Arithmetic - 1849 - 346 pages
...areas is equal to the difference of the squares of the diameters multiplied by 0.7854. PROBLEM VII. — To find the solidity of a prism, or of a cylinder. RULE. Multiply the area of the base by the altitude. B. VII., Prop. XI.) (Geometry, EXAMPLES. 1. How many cubic feet in a rectangular stick of... | |
 | Almon Ticknor - Measurement - 1849 - 156 pages
...whose base is 16 inches, and its length 20 feet ? , Ans. 86-5685 feet. PROBLEM 8. To find the solidity of a cylinder. RULE. — Multiply the area of the base by the perpendicular height of the cylinder, and the product will be the solidity. 1. What is the solidity of a cylinder, the diameter... | |
 | Benjamin Greenleaf - Arithmetic - 1849 - 336 pages
...roller 12 feet long and 2 feet in diameter; what is its convex surface ? ART. 339. To find the solidity of a cylinder. RULE. — Multiply the area of the base by the altitude, and the product will be the solidity. 1. What is the solidity of a cylinder, 8 feet in length... | |
 | J. M. Scribner - Mechanical engineering - 1849 - 286 pages
...base 3 feet 3x3-14159=9-42477 Then, 9-42477x23=216-76971= surface. PBOBLEM IL To find the Solidity of a Cylinder. Rule. — Multiply the area of the base by the height, and the pro duct will give the solid contents. Examples — 1. What is the solidity of a cylinder,... | |
 | George Roberts Perkins - Arithmetic - 1850 - 364 pages
...equal to the difference of the squares of the diameters multiplied by 0-7854. PROBLEM VII. — To Jind the solidity of a prism, or of a cylinder. RULE. Multiply the area of the base by the altitude. B. VII., Prop. XI.) (Geometry, EXAMPLES. 1. How many cubic feet in a rectangular stick of... | |
 | Charles Davies - Arithmetic - 1850 - 412 pages
...called the convex surface. 340. To find the convex surface of a right prism, Multiply the perimeter of the base by the perpendicular height, and the product will be the convex surface (Bk. VH. Prop. I). EXAMPLES. 1. What is the convex surface of a prism whose base is... | |
 | John Radford Young - Measurement - 1850 - 294 pages
...1801b. to a cubic foot?* Ans. 764 tons, nearly. PROBLEM II. — To find the solid content of a prism or cylinder. RULE. Multiply the area of the base by the perpendicular height of the prism or cylinder, and the product will be the area. The truth of this rule may be established... | |
 | Charles Davies - Geometry - 1850 - 238 pages
...circumference of the base 8 feet 4 inches. Ans. 116,6666, &c., sq. ft. PROBLEM II. To find the solidity of a cylinder. RULE. Multiply the area of the base by the altitude, and the product will be the solidity. EXAMPLES. 1. What is the solidity of a cylinder, the... | |
 | George Roberts Perkins - Arithmetic - 1851 - 356 pages
...is equal to the difference of the squares of the diameters multiplied by 0-7854. PROBLEM VII.—To find the solidity of a prism, or of a cylinder. RULE. Multiply the area of the base by the altitude. (Geometry, R VII., Prop. XI.) EXAMPLES. 1. How many cubic feet in a rectangular stick of... | |
 | James Elliot - 1851 - 152 pages
...its bulk ? * PROBLEM II. Ans. 3•78 -. To find the Solidity of a Cone or Pyramid (Right or Oblique). RULE. Multiply the area of the base by the perpendicular height, and divide the product by 3. FORMULA. S= A * H * This is the famous problem of doubling the cube proposed... | |
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To find the solidity of a cylinder. RULE. — Multiply the area of the base by the altitude, and the product will be the solidity. 
