 | William Kent - Engineering - 1902 - 1204 pages
...work is made by obtaining the last two figures of the root by division, the divisor employed being three times the square of the part of the root already found; thus, after finding the first three figures: 8x 123J = 45387|20498963|45.1 + —181548 234416 826985... | |
 | Webster Wells - Algebra - 1904 - 642 pages
...and write its square root as the first digit of the root; subtract the square of the first root-digit from the left-hand period, and to the result annex the next period. Divide this remainder, omitting the last digit, by twice the part of the root already found, and annex the quotient to the... | |
 | Henry Burchard Fine - Algebra - 1904 - 616 pages
...indicated above. Observe that each new figure of the root is found by dividing the remainder last obtained by three times the square of the part of the root already found ; thus, we find the significant figure of b by dividing flj by 3a2, and c by dividing A'2 by 3(o +... | |
 | William Kent - Engineering - 1902 - 1224 pages
...work is made by obtaining the last two figures of the root by division, the divisor employed being three times the square of the part of the root already found; thus, arter finding the first three figures: 8 x 123a = 45387|20498963|45.1 + —181548 — 834416... | |
 | John Henry Tanner - Algebra - 1904 - 398 pages
...the first term of the remainder by the first term of the trial divisor,— the trial divisor being three times the square of the part of the root already found. By continuing this process all the terms of tlxe required root may be found. The work of finding the... | |
 | John Charles Stone, James Franklin Millis - Algebra - 1905 - 776 pages
...term of the root, 6, may be obtained by dividing the first term of this remainder, 3«26, by За2, or three times the square of the part of the root already found. This divisor, Заг, is the trial divisor. If to the trial divisor we add Зоб, or three times the... | |
 | Webster Wells - Algebra - 1906 - 484 pages
...root as the first digit of the root; subtract the square of the first root-digit from the lefl-hand period, and to the result annex the next period. Divide this remainder, omitting the last digit, by twice the part of the root already found, and annex the quotient to the... | |
 | Webster Wells - Algebra - 1906 - 550 pages
...obtained, and subtract the product from the remainder. If other terms remain, proceed as before, taking three times the square of the part of the root already found for the next trialdivisor. 226. Examples. » 8х?-3вх<у + 54 zy - 27 у» [ 2 а? - 3 у Sa* - 36... | |
 | George Albert Wentworth - Algebra - 1906 - 440 pages
...than the number of figures already obtained may be found without error by division, the divisor being three times the square of the part of the root already found. EXERCISE 91 Find the cube root of : 1. 103,823. . 3. 8741.816. 5. 6,148,602.368. 2. 262,144. 4. 410.172407.... | |
 | Webster Wells - Algebra - 1908 - 262 pages
...write its square root as the first digit of the root ; subtract the square of the first root.digit from the left-hand period, and to the result annex the next period. Divide this remainder, omitting the last digit, by twice the part of the root already found, and annex the quotient to the... | |
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Divide this remainder by three times the square of the part of the root already found, with two ciphers annexed, and write the quotient as the next figure of the root. 
