 | Michael Walsh - Arithmetic - 1828 - 318 pages
...cross wise. • 3. If the errors are alike, that is, both greater or both loss than the given number, divide the difference of the products by the difference of the errors, and the quotienl is the answer: But if Ihe errors be unlike, divide the sum of the products by the sum of the... | |
 | William Slocomb - 1828 - 160 pages
...first error. k 4. If the errojrs be alike, that is both greater, or both less than the given number, divide the difference of the products by the difference of the errors; but if the errors be unlike, divide the sum of the products by the sura of the errors; and in either... | |
 | James L. Connolly (mathematician.) - Arithmetic - 1829 - 266 pages
...the last supposed number by the first error. It' the errors are alike, divide the difference of their products by the difference of the errors, and the quotient will be the answer. If the errors are unlike, divide the sum ot their products by the sum of the errors, and the quotient... | |
 | Nathan Daboll - Arithmetic - 1829 - 252 pages
...results in the question. 3. Multiply the first position by the last error, and the last position by tiie first error. 4. If the errors are alike, divide the difference of ihe products by the difference of the errors, and the quotient will be the answer. 5. If the errors... | |
 | William Kinne - 1829 - 246 pages
...in the question. 3. Multiply each of the errours by the contrary supposition. 4. 1f the errours be alike, divide the difference of the products by the difference of the errours, and the quotient will be the answer. 5. 1f the errours be unlike, divide the sum of the products... | |
 | Thomas Tucker Smiley - 1830 - 188 pages
...4. Observe whether the errors are both of the same kind ; ie both too great, or both too little. 5. If the errors are alike, divide the difference of...products by the difference of the errors, and the product will be the true number or answer. But if the errors are one too great and the other too little,... | |
 | Nathan Daboll - Arithmetic - 1831 - 246 pages
...different from the results in the question. 3. Multiply }he first position by the last error, and the las; position by the first error. 4. If the errors are...by the difference of the errors, and the quotient wii, be the answer. 5. If the errors are unlike, divide the sum of the products by the sum of the errors,... | |
 | Michael Walsh - 1831 - 348 pages
...them crosswise. 3. If the errors are alike, that is, both greater or both less than the given number, divide the difference of the products by the difference of the errors, and the quotient is the answer ; but if the errors be unlike, divide the sum of the products by the sum of the errors,... | |
 | William Kinne - Accounting - 1831 - 248 pages
...in the question. 3. Multiply each of the errours by the contrary supposition. 4. If the errours be alike, divide the difference of the products by the difference of the errours, and the quotient will be the answer. 5. If the errours be unlike, divide the sum of the products... | |
 | Nicolas Pike - Arithmetic - 1832 - 540 pages
...negative, x will be equal te Tft-j-SO 4. If the errors be alike, that is, both too small or both too great, divide the difference of the products by the difference...the quotient will be the answer. 5. If the errors be unlike ; that is, one too small, and the other too great, divide the sum of the products by the... | |
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If the errors are alike, divide the difference of the products by the difference of the errors, and the quotient will be the answer. 
