 | George Roberts Perkins - Arithmetic - 1849 - 344 pages
...cent., and the interest, to find the principal. By the reverse of the last problem, we obtain this RULE. Divide the given interest by the interest of $1 for the given time and given rate per cent.; and the quotient will be the number of dollars in the principal. EXAMPLES. 1.... | |
 | George Roberts Perkins - Arithmetic - 1849 - 346 pages
...the interest on $1, as the given sum is times greater than $1. Hence, •we have the following RULE. Divide the given interest by the interest of $1, for the given time, and given rate per cent. EXAMPLES. 1. The interest on a certain principal, for 9 months and 10 days, at... | |
 | Rufus Putnam - Arithmetic - 1849 - 276 pages
...require as many dollars for the principal as there are times 6 cents in $50. Ans. $833.33 \. RULE. Divide the given interest by the interest of $1 for the given time. 8. What sum of money on interest at 5J per cent. will yield $75 semi-annually ? 9. What sum of money... | |
 | Charles Guilford Burnham - 1850 - 350 pages
...interest of $1 for the given time, we shall obtain the principal required, as before. Hence the RULE. Divide the given interest by the interest of $1 for the given time, and the quotient will be the answer. 2. What principal will gain $19 in 4 months, at 6 per cent. ? Ans.... | |
 | George Roberts Perkins - Arithmetic - 1850 - 364 pages
...than the interest on $1, as the given sum is times greater than $1. Hence, we have the following RULE. Divide the given interest by the interest of $1, for the given time, and given rate per cent. EXAMPLES. 1. The interest on a certain principal, for 9 months and 10 days, at... | |
 | Roswell Chamberlain Smith - Arithmetic - 1850 - 314 pages
...What to draw 30 cents'? — 50 cents? — $7.50?— $81.97|? A. $2; $3; $5; $75; $819.75. RULE. 4. Divide the given interest by the interest of $1, for the given rate and time, the quotient will be the required principal. 5. What sum of money put at interest 1... | |
 | George Roberts Perkins - Arithmetic - 1851 - 356 pages
...the interest on $1, as the given sum is times greater than $1. Hence, we have the following RULE. ' * Divide the given interest by the interest of $1, for the given time, and given rate per cent. EXAMPLES. 1. The interest on a certain principal, for 9 months and 10 days, at... | |
 | Charles Haynes Haswell - Engineering - 1851 - 346 pages
...The Time, Rate per Cent., and Interest being given, to find the ,,.,,, ,.- Principal. iii.-i,E . — Divide the given Interest, by the interest of $1, for the given rate and time. ... ... EXAMPLE. — What Bum of money at 6 per cent, will in 14 months gain $14 ? :... | |
 | James Bates Thomson - Arithmetic - 1855 - 436 pages
...expressed in decimals ; and the quotient will be the principal required. Or, make the interest of $1 for the given time and rate, the numerator, and 100...the denominator of a common fraction ; then divide tie given interest by this fraction, and the quotient will be the prinupd required. (Art. 234.) , 13.... | |
 | Roswell Chamberlain Smith - Arithmetic - 1856 - 334 pages
...What to draw 30 cents? — 50 cents » — $7.50?— $81.971? A. f3; 83; $5; S75 ; $819.76. RULE. 4. Divide the given interest by the interest of $1, for the given rate and time, the quotient will be the required principal. 5. What sum of money put at interest 1... | |
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RULE. Divide the given interest by the interest of $1 for the given time, and the quotient will be the answer. 
