 | Elias Loomis - Algebra - 1873 - 396 pages
...quotient. 3. Multiply the whole divisor by this term, and subtract the product from the dividend. 4. Divide the first term of the remainder by the first...the divisor, for the second term of the quotient. 5. Multiply the whole divisor by this term, and subtract the product from the last remainder. 6. Continue... | |
 | William Guy Peck - Algebra - 1875 - 348 pages
...of the quotient. Multiply the divisor by this term, and subtract the product from the dividend. III. Divide the first term of the remainder by the first...for the second term of the quotient. Multiply the divisor by this term, and subtract the product from the first remainder, and so on. IV. Continue the... | |
 | William Guy Peck - Algebra - 1875 - 348 pages
...this term, and subtract the product from the dividend. III. Divide the first term of the remainder bi/ the first term of the divisor, for the second term of the quotient. Multiply the divisor by this term, and subtract the product from the first remainder, and so on. IV. Continue the... | |
 | Charles Scott Venable - Algebra - 1880 - 168 pages
...divisor, for the first term of the quotient. Then multiply the divisor by the first term of the quotient, and subtract the product from the dividend. Divide...of the remainder by the first term of the divisor, and proceed as before, continuing the process with the terms that remain. Ex. 1. Divide x' + iax +... | |
 | George Albert Wentworth - Algebra - 1881 - 406 pages
...p, the second term of the quotient. That is, the second term of the quotient is obtained by dividing the first term of the remainder by the first term of the divisor. In like manner, the third term of the quotient is obtained by dividing the first term of the new remainder... | |
 | William James Milne - Algebra - 1881 - 360 pages
...the root, we consider z2 + 2z as one quantity, which we multiply by 2 for the trial divisor. Dividing the first term of the remainder by the first term of the divisor, the third term of the root is obtained, which is — 5. Annexing this, as before, to the trial divisor... | |
 | Simon Newcomb - Algebra - 1882 - 302 pages
...quotient. 3. Multiply the whole divisor by this quotient, and subtract the product from the dividend. 4. Divide the first term of the remainder by the first term of the divisor, and repeat the process until the divisor will no longer divide the remainder. REMARK. Unless we introduce... | |
 | James Hamblin Smith - 1883 - 466 pages
...the expression 3ab + 62 we obtain the full divisor 3a2 + 3ab + V. Hence our rule proceeds thus : " Divide the first term of the remainder by the first term of the divisor, and add ~the result to the first term of the root. Then take three times the product of the first and... | |
 | Edwin Pliny Seaver, George Augustus Walton - Algebra - 1881 - 304 pages
...terms of the remainder in the same way that the terms of the dividend and divisor have been arranged. Divide the first term of the remainder by the first term of the divisor, and the result is the second term of the quotient. Multiply the divisor by this term, and subtract... | |
 | George Albert Wentworth - Algebra - 1886 - 284 pages
...p, the second term of the quotient. That is, the second term of the quotient is obtained by dividing the first term of the remainder by the first term of the divisor. In like manner, the third term of the quotient is obtained by dividing the first term of the new remainder... | |
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Then divide the first term of the remainder by the first term of the divisor... 
