| Adrien Marie Legendre - Geometry - 1857 - 444 pages
...is equal to twice as many right angles as the polygon has sides. Again, the sum of all the interior **angles is equal to twice as many right angles as the figure has sides,** less four right angles (p. 26). Hence, the interior angles plus four right angles, is equal to twice... | |
| William Mitchell Gillespie - Surveying - 1857 - 538 pages
...proposition of Geometry, that in any figure bounded by straight lines, the sum of all the interior **angles is equal to twice as many right angles, as the figure has sides** less two ; since the figure can be divided into that number of triangles. Hence this common rule. "... | |
| W. Davis Haskoll - Civil engineering - 1858 - 324 pages
...and in an irregular polygon they may be all unequal. The interior angles of a polygon are together **equal to twice as many right angles as the figure has sides,** less four. On this is based the theory of the traverse, of which further explanation will be given... | |
| Elias Loomis - Conic sections - 1858 - 234 pages
...that is, together with four right angles (Prop. V., Cor. 2). Therefore the angles of the polygon are **equal to twice as many right angles as the figure has sides,** wanting four right angles. Cor. 1. The sum of the angles of a quadrilateral is four right angles ;... | |
| Charles Hutton - Mathematics - 1860 - 1022 pages
...outward angles, is equal Ui t »ice as many right angles as the figure has sides. But the sum of all tbr **inward angles, with four right angles, is equal to twice as many right angles as** ttx figure has sides (th. 19). Therefore the sum of all the inward and all the oetward angles, is equal... | |
| Horatio Nelson Robinson - Geometry - 1860 - 472 pages
...triangles is equal to two right angles, (Th. 11) ; and the sum of the angles of all the triangles must be **equal to twice as many right angles as the figure has sides.** But the sum of these angles contains the sum of four right angles about the point p ; taking these... | |
| Royal college of surgeons of England - 1860 - 336 pages
...two right angles ; and all the angles of any rectilineal figure, together with four right angles, are **equal to twice as many right angles as the figure has sides.** 6. The opposite sides and angles of parallelograms are equal to one another, and the diameter bisects... | |
| 1860 - 462 pages
...must be aliquot parts of the circle or of four right angles. All the angles of any such figure are **equal to twice as many right angles as the figure has sides** minus four right angles, or if « be the number of sides, the sum of all the angles is (2n — 4) right... | |
| William Mitchell Gillespie - Surveying - 1880 - 570 pages
...proposition of Geometry, that in any figure bounded by straight lines, the sum of all the interior **angles is equal to twice as many right angles, as the figure has sides** less two ; since the figure can be divided into that number of triangles. Hence this common rule. "... | |
| William Frothingham Bradbury - Geometry - 1880 - 260 pages
...sides minus two. Let ABCDEF be the given polygon ; the sum of all the interior angles A, B, C, D, E, F, **is equal to twice as many right angles as the figure has sides** minus two. For if from any vertex A, diagonals AC, AD, AE, are drawn, the polygon will be divided into... | |
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