| Charles Davies - Geometry - 1854 - 436 pages
...right angles as the figure has sides, less four right angles (P. 26). Hence, the interior angles plus **four right angles, is equal to twice as many right angles as the** polygon has sides, and consequently, equal to the sum of the interior angles plus the sum of the exterior... | |
| E. W. Beans - Surveying - 1854 - 114 pages
...taken. If the entire survey has been made as above directed, the sum of all the internal angles will be **equal to twice as many right angles as the figure has sides,** diminished by four right angles. If this sum, as in practice will be likely to be the case, should... | |
| Popular educator - 1854
...into three equal parts. *"'t 3Fig. .42. No. 3. interior angles together with four right angles are **equal to twice as many right angles as the figure has sides.** Therefore all the interior angles together with all the exterior angles are equal (Ax. 1) to all the... | |
| William Mitchell Gillespie - Surveying - 1855 - 436 pages
...proposition of Geometry, that in any figure bounded by straight lines, the sum of all the interior **angles is equal to twice as many right angles, as the figure has sides** less two ; since the figure can be divided into that number of triangles. Hence this common rule. "... | |
| Euclides - 1855 - 270 pages
...and there are as many triangles in the figure as it has sides, all the angles of these triangles are **equal to twice as many right angles as the figure has sides.** But all the angles of these triangles are equal to the interior angles of the figure, viz. ABС, BСD,... | |
| Charles Davies - Geometry - 1855 - 336 pages
...triangles is equal to two right angles (Th- xvii) : hence, the sum of the angles of all the triangles **is equal to twice as many right angles as the figure has** sidesBut the sum of all the angles about the point P is equal to four right angles (Th- ii- Cor- 4)... | |
| William Mitchell Gillespie - Surveying - 1856 - 478 pages
...proposition of Geometry, that in any figure bounded by straight lines, the sum of all the interior **angles is equal to twice as many right angles, as the figure has sides** less two ; since the figure can be divided into that number of triangles. Hence this common rule. "... | |
| Euclides - 1856 - 168 pages
...with four right angles. Therefore all the angles of the figure, together with four right angles, are **equal to twice as many right angles as the figure has sides.** XVI. If two triangles have two sides of the one equal to two sides of the other, each to each, and... | |
| Cambridge univ, exam. papers - 1856 - 200 pages
...Prove that all the internal angles of any rectilineal figure, together with four right angles, are **equal to twice as many right angles as the figure has sides;** and that all the external angles are together equal to four right angles. In what sense are these propositions... | |
| Henry James Castle - Surveying - 1856 - 220 pages
...angles are the exterior angles of an irregular polygon ; and as the sum of all the interior angles are **equal to twice as many right angles, as the figure has sides,** wanting four ; and as the sum of all the exterior, together with all the interior angles, are equal... | |
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