 | John Playfair - Euclid's Elements - 1837 - 332 pages
...them being a right angle, adding to each the angle ABC, the whole angle DBA will be equal (2. Ax.) to the whole FBC ; and because the two sides AB, BD,...equal to the angle FBC, therefore the base AD is equal (4. 1.) to the base FC, and the triangle ABD to the triangle FBC. But the parallelogram BL is double... | |
 | Andrew Bell - Euclid's Elements - 1837 - 290 pages
...right angle, add to each the angle ABC, and the whole angle DBA is equal to the whole FBC (Ax. 2) ; and because the two sides AB, BD, are equal to the...and the angle DBA equal to the angle FBC, therefore (I. 4) the base AD is equal to the base FC, and the triangle ABD to the triangle FBC. Now, the parallelogram... | |
 | Euclid, James Thomson - Geometry - 1837 - 410 pages
...of them being a right angle, add to each the angle ABC, and the whole angle DBA is equal (I. nx. 2.) to the whole FBC : and because the two sides AB, BD are equal (const.) to the two FB, BC, each to each, and the angle DBA equal to FBC ; therefore the triangle ABD... | |
 | Euclid - Geometry - 1838 - 470 pages
...each of them being a right angle, add to each the angle ABC, and the whole angle DBA is equal (2. Ax.) to the whole FBC : and because the two sides AB, BD are equal to the two DLE FB, BC, each to each, and the angle DBA equal to the angle FBC ; therefore,the base AD is equal... | |
 | Euclides - 1838 - 264 pages
...angle FBA, tso Def. each of them being a rightf angle, add to each the angle ABC ; therefore the whole angle DBA is equal* to the whole FBC : and because the two sides AB, BD, are equalt to the two FB, BC, encb to each, and the angle DBA equ.il to the angle FBC ; therefore the ba««... | |
 | Robert Simson - Geometry - 1838 - 434 pages
...each of them being a right angle, add to each the angle ABC, and the whole angle DBA is equal (2. Ax.) to the whole FBC : and because the two sides AB, BD are equal to the two DLE FB, BC, each to each, and the angle DBA equal to the angle FBC ; therefore^the base AD is equal... | |
 | Euclides - Geometry - 1841 - 378 pages
...the same reason, CF is equal to FD: and because AD is equal to BC, and AF to FB, the two sides FA, AD are equal to the two FB, BC, each to each; and the base DF was proved equal to the base FC; therefore the angle FAD is equal * to the angle FBC. Again,... | |
 | John Playfair - Euclid's Elements - 1842 - 332 pages
...them being a right angle, adding to each the angle ABC, the whole angle DBA will be equal (2. Ax.) to the whole FBC ; and because the two sides AB, BD,...equal to the angle FBC, therefore the base AD is equal (4. 1.) to the base FC, and the triangle ABD to the triangle FBC. But the parallelogram BL. is double... | |
 | Euclides - 1842 - 316 pages
...FBA, each of them being a right angle, add to each the angle AB c ; the whole angleDB Aisequal(2. Ax.) to the whole FBC; and because the two sides AB, BD are equal to the two FB, B c, each to each, and the angle DBA equal to the angle FBC; therefore the base AD is equal (4. 1.)... | |
 | Euclid, James Thomson - Geometry - 1845 - 382 pages
...of them being a right angle, add to each the angle ABC, and the whole angle DBA is equal (I. ax. 2) to the whole FBC : and because the two sides AB, BD are equal (const.) to the two FB, BC, each to each, and the angle DBA equal to FBC ; therefore the triangle ABD... | |
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FBC ; and because the two sides AB, BD are equal to the two FB, BC, each to each, and the angle DBA equal to the angle FBC; therefore the base AD is equal (i. 
