 | Edward Brooks - Arithmetic - 1876 - 588 pages
...root ; their sum will be the COMPLETE DIVISOR. V. Multiply the COMPLETE DIVISOR by the last term of the root ; subtract the product from the dividend, and to the remainder annex the next period for a new dividend. Take 3 times the square of the root now found, regarded as... | |
 | Joseph Ray - Arithmetic - 1877 - 350 pages
...on the right of the trial divisor. Prie. 2П. 4. Multiply the complete divisor by the last figure of the root; subtract the product from the dividend,...remainder bring down the next period for a new dividend. 5. Double the whole root found, for a new trial divisor, and continue the operation in the same manner... | |
 | Horatio Nelson Robinson, Daniel W. Fish - Arithmetic - 1877 - 372 pages
...the result will be the complete divisor. V. Multiply the complete divisor by the trial figure, and subtract the product from the dividend, and to the remainder bring down the next jjeriodfor a new dividend. VI. Add the square of the last figure of the root, the last term in column... | |
 | Joseph Ray - Arithmetic - 1877 - 402 pages
...trial divisor ; the sum is the complete divisor. 5. Multiply the complete divisor by the last figure of the root; subtract the product from the dividend, and to the remainder bring floirn the next period for a new dividend. 6. Find a new trial divisor as before, and continue the... | |
 | William Guy Peck - Arithmetic - 1877 - 430 pages
...trial divisor for a complete divisor. IV. Multiply the divisor thus completed by the trial -figure of the root, subtract the product from the dividend, and to the remainder annex the following period for a new dividend. V. Proceed as before, continuing the operation till... | |
 | James Bates Thomson - Algebra - 1878 - 322 pages
...place the result in the quotient. II. Multiply the wl&U divisor by the term placed in the quotient ; subtract the product from the dividend, and to the remainder bring down as many terms of the dividend as the case may require. Repeat the operation till all the terms of the... | |
 | Elias Loomis - Algebra - 1879 - 398 pages
...the square of the second figure. 5th. Multiply the divisor thus increased by the last figure ofttie root ~ subtract the product from the dividend, and...remainder bring down the next period for a new dividend. 6th. Take three hundred times the square of the whole root now found for a new trial divisor, and by... | |
 | Shelton Palmer Sanford - Algebra - 1879 - 348 pages
...trial divisor to form• the complete divisor. III. Multiply the complete divisor by the second term of the root, subtract the product from the dividend, and to the remainder bring down as many terms as may be necessary for a new dividend. IV. Double the terms of the root already found... | |
 | Clement Mackrow - 1879 - 552 pages
...the dividend, and it will be the second figure of the root. From the dividend subtract the product, and to the remainder bring down the next period for a new dividend ; double the figures in the quotient for a divisor, and continue the operation as above till all the... | |
 | Horatio Nelson Robinson - Algebra - 1879 - 332 pages
...result will be the complete divisor. V. Multiply the complete divisor by the last figure cf the roof, subtract the product from the dividend, and to the remainder bring down another period for a new dividend. VI. Add together the square of the last figure of the root, the... | |
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Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
