| George Egbert Fisher - 1900 - 444 pages
...This example illustrates the following method of multiplying a multinomial by a multinomial : Multiply each term of the multiplicand by each term of the multiplier, and add algebraically the resultгng products. In general, (a + 6) (c + d - e) = a (c + d - e) + b (c + d -... | |
| George Egbert Fisher, Isaac Joachim Schwatt - Algebra - 1901 - 646 pages
...article is derived the following principle for multiplying a multinomial by a multinomial : Multiply each term of the multiplicand by each term of the multiplier, and add algebraically the resulting products. Ex. 1. Multiply -3a + 2b by 2a-3b. We have (-3a + 26)(2a - 36)... | |
| George Egbert Fisher - 1901 - 622 pages
...This example illustrates the following method of multiplying a multinomial by a multinomial : Multiply each term of the multiplicand by each term of the multiplier, and add algebraically the resulting products. In general, (a + *)(c + </- e) = a(c + d- e) + b(c + </-e) =... | |
| American School (Lansing, Ill.) - Algebra - 1902 - 80 pages
...other words if both multiplier and multiplicand, are polynomials we proceed in the same way ; multiply each term of the multiplicand by each term of the multiplier and add the products. In performing multiplication of polynomials the signs are of utmost importance. 57. Example.... | |
| Louis Parker Jocelyn - Algebra - 1902 - 460 pages
...с'+3 by fi^frV*, and check. 100. PROBLEM 3. To multiply a polynomial by a polynomial. Rule. Multiply each term of the multiplicand by each term of the multiplier, and add the partial product». Dem. This is the most general case of law C, ie, (a + b + c)x = ax + bx + ex.... | |
| American School (Chicago, Ill.) - Engineering - 1903 - 426 pages
...other words if both multiplier and multiplicand, are polynomials we proceed in the same way ; multiply each term of the multiplicand by each term of the multiplier and add the products. In performing multiplication of polynomials the signs are of utmost importance. 57. Example.... | |
| John Marvin Colaw - Algebra - 1903 - 444 pages
...From the above is derived the following method of multiplying a polynomial by a polynomial : Multiply each term of the multiplicand by each term of the multiplier, and add the products (algebraically). 1 . Multiply a? + 3 j?y + 3 xy- + y3 by x + y. v> + 3 xy + 3 xy- +•... | |
| John Henry Walsh - Algebra - 1903 - 288 pages
...+ 2 a; Multiplying x + 2 by 3, 3 x + 6 Adding the two parts of the product, x2 + 5 ж + 6 Multiply each term of the multiplicand by each term of the multiplier and combine the products. 2. Multiply x + 3 by x — 4. x + S a;-4 ж2 - x - 12 Multiply : 3. х + ЗЪух... | |
| Webster Wells - Algebra - 1904 - 642 pages
...whatever the number of terms in the multiplicand or multiplier. We then have the following rule : Multiply each term of the multiplicand by each term of the multiplier, and add the partial products. 1. Multiply 3a-4& by 2(i-5b. In accordance with the rule, we multiply За —... | |
| Henry Burchard Fine - Algebra - 1904 - 616 pages
...like or unlike signs. 2. To find the product of a polynomial by a monomial or polynomial, multiply each term of the multiplicand by each term of the "multiplier and add the products thus obtained. The first rule follows from the commutative and associative laws and the... | |
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