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" ... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained... "
Ticknor's Mensuration, Or, Square and Triangle: Being a Practical and ... - Page 13
by Almon Ticknor - 1849 - 144 pages
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A New Practical and Theoretical Arithmetic: In Which, in Addition to the ...

Horatio Nelson Robinson - Arithmetic - 1854 - 306 pages
...period, and set its root on the right of the given number; subtract said square from the left-hand period, and to the remainder bring down the next period for a dividual. 3. Double the root for a divisor, and fry how often this divisor (with the figure used in...
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Arithmetic on the Productive System: Accompanied by a Key and Cubical Blocks

Roswell Chamberlain Smith - Arithmetic - 1856 - 334 pages
...last period on the left, write its root on the right, as a quotient, subtract the square from the said period, and to the remainder bring down the next period for a dividend. 16. Double the root (quotient) for a partial divisor, and on its right, place, for the total divisor,...
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Practical Arithmetic, by Induction and Analysis

Joseph Ray - Arithmetic - 1857 - 348 pages
...its root on the right. like a quotient in division. Subtract the square of this root from the left period, and to the remainder bring down the next period for a dividend. 3. Double the .root found, and place it on the left for a trial divisor. Find how many times the divisor...
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Burnham's Arithmetic, Revised: A New System of Arithmetic, on an Improved ...

Charles Guilford Burnham - Arithmetic - 1857 - 328 pages
...the left-hand period, and place its root as a quotient in division. III. Subtract the cube from said period, and to the remainder bring down the next period, for a dividend. IV. Multiply the square of the quotient by 300, calling it the triple square, and the, quotient by...
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Introduction to The National Arithmetic: On the Inductive System : Combining ...

Benjamin Greenleaf - Arithmetic - 1857 - 336 pages
...the left-hand period, and place its root on • the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by ZOO for a divisor, by which divide the dividend, and...
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Ray's Algebra, Part Second: An Analytical Treatise, Designed for ..., Part 2

Joseph Ray - Algebra - 1857 - 408 pages
...right, after the manner of a quotient in division. Subtract the square of the root from the left per'od, and to the remainder bring down the next period for a dividend. 3rd. Double the root already found, and place it on the left for a divisor. Find how many times the...
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The National Arithmetic on the Inductive System: Combining the Analytic and ...

Benjamin Greenleaf - Arithmetic - 1857 - 452 pages
...period, and write its root as the first figure of the required root. From that period subtract the cube, and to the remainder bring down the next period for a dividend. Multiply the square of the root figure by 3, and to the product annex two ciphers for a trial divisor,...
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A New System of Arithmetic, on an Improved Plan, Embracing the Rules of ...

Charles Guilford Burnham - 1857 - 342 pages
...quotient in division. Place the square of the root found, under said period, and subtract it therefrom, and to the remainder bring down the next period, for a dividend. III. Double the root already found, for a divisor ; see hoie often the divisor is contained in the...
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Practical Arithmetic: Uniting the Inductive with the Synthetic Mode of ...

James Bates Thomson - Arithmetic - 1858 - 400 pages
...the first period on the left hand ; then placing its root on the right of the number, subtract the cube from the period, and to the remainder bring down the next period for a dividend. III. Square the part of the root thvs found with a cipher annexed to it ; multiply this square Ъу...
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Introduction to The National Arithmetic: On the Inductive System Combining ...

Benjamin Greenleaf - Arithmetic - 1858 - 332 pages
...in the left-hand period, and place its root on the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by 300 for a divisor, by which divide the dividend, and...
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