 | Stephen Pike - Arithmetic - 1835 - 210 pages
...period, and set its root on the right of the given number: subtract said square from the left hand period, and to the remainder bring down the next period for a dividual. 3. Double the root for a divisor, and try hp\v often this divisor (with the figure used in... | |
 | Charles Potts - Arithmetic - 1835 - 202 pages
...hand period, and set its root on the right of the given number ; subtract said cube from the left hand period, and to the remainder bring down the next period for a dividual. 3. Square the root, and multiply the square by 3 for a defective divisor. 4. Reserve, mentally,... | |
 | James L. Connolly (mathematician.) - Arithmetic - 1835 - 264 pages
...not too great, of the first period, for the first figure of your root, subtract its cube from said period, and to the remainder bring down the next period for a resolvend. Take three times the square of the root for a defective divisor, and seek how often it is... | |
 | George Willson - Arithmetic - 1836 - 202 pages
...for the first figure of the root, and the square itself under the period, and subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Double the root already found, and annex a cipher to tho product, for a divisior. Seek how many times... | |
 | Silas Totten - Algebra - 1836 - 332 pages
...at the right, after the manner of a quotient in division. Subtract its cube from the aforementioned period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by 300, for a divisor. Seek how often the divisor is... | |
 | Mathematics - 1836 - 488 pages
...subtract from the highest period the greatest square contained in it, place the root in the quotient, and to the remainder bring down the next period for a dividend. 2. Double the root already found, (understanding a cypher at the right,) for a divisor, and divide... | |
 | Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...the left hand period, and place its root as a quotient in division. III. Subtract the cube from said period, and to the remainder bring down the next period for a dividend. IV. Multiply the square of the quotient by 300, calling it the triple square, and the quotient by 30,... | |
 | Peirpont Edward Bates Botham - Arithmetic - 1837 - 252 pages
...left hand period, and subtract it from that period. Place the root of this square in the quotient. To the remainder bring down the next period for a dividend. 3. Double the root already found (understanding a cipher at the righti for a divisor. Divide the dividend... | |
 | Luther Ainsworth - Arithmetic - 1837 - 298 pages
...for the first figure of the root, and place the cube under the first period, subtract it therefrom, and to the remainder, bring down the next period for a dividend. Q. You have now found one figure of the root, what is your next process ? A. Multiply the square of... | |
 | Arithmetic - 1838 - 218 pages
...place. Find the greatest cube in the left hand period, and set its root in the quotient; subtract said cube from the period, and to the remainder bring down the next period for a dividual. Square the root, and multiply the square by three hundred for a divisor. See how often the... | |
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... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained... 
