| Andrew Wheeler Phillips, Irving Fisher - Geometry, Modern - 1896 - 276 pages
...AC and AE. To PROVE — angle m is measured by \ (arc CE — arc BD). Join CD. Then m + w=s. § 59 [An exterior angle of a triangle is equal to the sum of the two opposite interior angles.] Hence m = s—w. Ax. 3 But s is measured by i arc CE. § 197 And... | |
| Andrew Wheeler Phillips, Irving Fisher - Geometry - 1896 - 554 pages
...secants, AC and AE. To PROVE — angle m is measured by ^ (arc CE— arc BD). Join CD. Then m -\-ws. § 59 [An exterior angle of a triangle is equal to the sum of the two opposite interior angles.] Hence m = s — tv. But s is measured by £ arc CE. And w is measured... | |
| James Howard Gore - Geometry - 1898 - 232 pages
.../ A + Z £ + Z J3CM = 2 right angles. QED 80. COR. 1. Equation (a) when expressed in words is : the exterior angle of a triangle is equal to the sum of the two interior and opposite angles. 81. COR. 2. If two angles of a triangle are given, or merely their sum, the third... | |
| Webster Wells - Geometry - 1898 - 264 pages
...85. Cor. I. It follows from the above demonstration that Z.BCD = Z.ECD + Z.BCE = ZA + ZB; hence 1. An exterior angle of a triangle is equal to the sum of the two opposite interior angles. 2. An exterior angle of a triangle is greater than either of the... | |
| F. J. Beck - 1899 - 288 pages
...of it. 5. Whaj: is a triangle? Name and define the different kinds of triangles. 6. Demonstrate: Any exterior angle of a triangle is equal to the sum of the two interior non-adjacent angles. 7. What is a quadrilateral? Name and define the three classes of quadrilaterals. 8. What is a polygon?... | |
| Webster Wells - Geometry - 1899 - 424 pages
...Cor. I. It follows from the above demonstration that Z BCD = Z ECD + Z J3OS = Z .4 + Z 5 ; hence 1. An exterior angle of a triangle is equal to the sum of the two opposite interior angles. 2. An exterior angle of a triangle is greater than either of the... | |
| George Albert Wentworth - Geometry - 1899 - 496 pages
...COR. 7. In an equiangular triangle, each angle is one third of two right angles, or 60°. 137. COR. 8. An exterior angle of a triangle is equal to the sum of the two opposite interior angles, and therefore greater than either of them. PROPOSITION XIX. THEOREM.... | |
| Charles Austin Hobbs - Geometry, Plane - 1899 - 266 pages
...COB. IV. In a right triangle, the two acute angles are complementary, Proposition 38. Theorem. 49. An exterior angle of a triangle is equal to the sum of the two opposite interior angles. COB. An exterior angle of a triangle is greater than either of the... | |
| George Albert Wentworth - Geometry, Modern - 1899 - 272 pages
...COR. 7. In an equiangular triangle, each angle is one third of two right angles, or 60°. 137. COR. 8. An exterior angle of a triangle is equal to the sum of the two opposite interior angles, and therefore greater than either of them. PROPOSITION XIX. THEOREM.... | |
| Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 394 pages
...equal respectively to the hypotenuse and an acute angle of the other. PROPOSITION XIII. THEOREM 100. An exterior angle of a triangle is equal to the sum of the two remote interior angles. B CD Hyp. Z ACD is an exterior angle of A ABC. To prove Z ACD = HIMT.... | |
| |