| James Bates Thomson - Arithmetic - 1847 - 426 pages
...multijily the divisor thus completed b;/ the figure last placed in the root ; subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend. IV. Double the root already found for a new partial divisor, divide, etc., as before, and... | |
| Charles Davies - Algebra - 1848 - 302 pages
...IV. Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend But if any of the products should be greater than the dividend, diminish the last figure of... | |
| George Roberts Perkins - Arithmetic - 1849 - 346 pages
...for its next term. Multiply this term by the. last found figure of the root, and subtract the product **from the dividend, and to the remainder bring down the next period for a NEW** DIVIDEND. Proceed as before until all the periods have been brought down. NOTE 1. — When any dividend... | |
| Nathan Daboll, David Austin Daboll - Arithmetic - 1849 - 260 pages
...figure under these two products, and call their amount the subtrahend. VIII. Subtract the subtrahend **from the dividend, and to the remainder bring down the next period for a new** dividend, with which proceed as before ; and so on till the whole is finished. Note 1. If the subtrahend... | |
| Roswell Chamberlain Smith - Arithmetic - 1850 - 314 pages
...quotient figure ; then add these three results together for a subtrahend. 17. Subtract the subtrahend **from the dividend, and to the remainder bring down the next period for a new** dividend, with which proceed as before, and so on till all the periods are brought down.* 18. NOTE.... | |
| Charles Guilford Burnham - 1850 - 350 pages
...write the cube of the last quotient figure, and call their sum the subtrahend. Subtract the subtrahend **from the dividend, and to the remainder bring down the next period, for a new** divtdend, and proceed as before, till the work is finished. EXAMPLES. 2. What is the cube root of 1906624... | |
| George Roberts Perkins - Arithmetic - 1850 - 364 pages
...for its next term. Multiply this term by the last found figure of the root, and subtract the product **from the dividend, and to the remainder bring down the next period for a NEW** DIVIDEND. Proceed as before until all the periods have been brought down. NOTE 1. — When any dividend... | |
| Benjamin Naylor - 1850 - 334 pages
...divisor. Multiply the divisor thus increased by the last figure in the root, and subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend. NOTE 1. — If there be a remainder after all the periods are brought down, annex ciphers... | |
| Benjamin Greenleaf - Arithmetic - 1850 - 368 pages
...quotient. NOTE. — One or two units, and sometimes three, must be allowed. 7. Subtract the subtrahend **from the dividend, and to the remainder bring down the next period for a new** dividend, with which proceed as before, and so on, till the whole is completed. NOTE. — The same... | |
| Charles Davies - Arithmetic - 1850 - 412 pages
...IV. Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend. But if the product should 'exceed the dividend, diminish the last figure of the root. V.... | |
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