| Horatio Nelson Robinson - Algebra - 1879 - 332 pages
...divisor. IV. Multiply the divisor thus completed by the last figure of the root ; subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend. V. Double the right-hand figure of the last complete divisor for a new divisor, and continue... | |
| Joseph Ray - Arithmetic - 1880 - 420 pages
...root and to tl,e divisor; then multiply the complete divisor by the quotient, subtract the product **from the dividend, and to the remainder bring down the next period** as before. 4. Double the root as before, place it on the left as a trial divisor, proceeding as with... | |
| H. Bryant - 1881 - 574 pages
...cube of the last rootfgurc, and find their sum, calling it the subtrahend. 7. Subtract the subtrahend **from the dividend, and to the remainder bring down the next period for a new** dividend, with which proceed as before till the required root be found. XOTES. — 1. When any dividend... | |
| James Morton - Circle-squaring - 1881 - 236 pages
...hand of the divisor and under the same, and multiply the divisor by this figure. Subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend, and so continue until all the periods are brought down. If any dividend shall be too small... | |
| William Allen Sylvester - Building - 1883 - 220 pages
...the complete divisor. 5. Multiply the complete divisor by the trial figure, and subtract the product **from the dividend ; and to the remainder bring down the next period for a new** dividend. 6. Add the square of the last figure of the root, the last term in column 2, and the complete... | |
| William Allen Sylvester - Carpentry - 1884 - 222 pages
...complete divisor by the trial HOUSE-CARPENTER'S COMPANION. figure in the root, and subtract the product **from the dividend ; and to the remainder bring down the next period for a new** dividend. 5. To the last complete divisor add the last figure of the root, and to the sum annex one... | |
| Benjamin Adams Hathaway - Arithmetic - 1885 - 190 pages
...to the divisor; then multiply the divisor by the last figure in the quotient, subtract the product **from the dividend, and to the remainder bring down the next period** as before.' Double the whole root as before and place it in the left as a second trial divisor, find... | |
| Frank Eugene Kidder - Architecture - 1886 - 640 pages
...divisor, multiply this final divisor by the number in the quotient just found, and subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend, and proceed as before. If it should be found that the trial divisor cannot be contained in... | |
| James Morton - Mathematics - 1887 - 236 pages
...hand of the divisor and under the same, and multiply the divisor by this figure. Subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend, and so continue until all the periods are brought down. Jf any dividend shall be too small... | |
| Horatio Nelson Robinson - 1888 - 372 pages
...complete divisor ; multiply the complete divisor by the trial figure in the root, and subtract the product **from the dividend, and to the remainder bring 'down the next period for a new** dividend. V. To the last complete divisor add the last figure of the root, and to the sum annex one... | |
| |