 | Shelton P. Sanford - Arithmetic - 1872 - 402 pages
...TRUE DIVISOR. IV. Multiply the TRUE DIVISOR by the second figure of the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Double the root already found for a NEW TRIAL DIVISOE, 5625(75 An, 49 145)725 725 continue... | |
 | Henry Beadman Bryant, Emerson Elbridge White, C. G. Stowell - Business mathematics - 1872 - 576 pages
...of the last root figure, and find their sum, calling it the subtraliend. 7. Subtract the subtrahend from the dividend, and to the re•mainder bring down the next period for a new dividend, ivilh which proceed as before till the required root be found. NOTES. — 1. When any dividend... | |
 | Ezra S. Winslow - Business mathematics - 1872 - 256 pages
...the divisor, as it now stands, by the figure last placed in the quotient, and subtract the product from the dividend, and to the remainder bring down the next period for a dividend, as before. 5. Multiply the quotient (now consisting of 3 figures) by 2, as before, and take... | |
 | Elias Loomis - Algebra - 1873 - 396 pages
...Multiply the divisor thus increased by the last figure of the root ; subtract the product from Hie dividend, and to the remainder bring down the next period for a new dividend. 6th. Take three hundred times the square of the whole root now found for a new trial divisor,... | |
 | Horatio Nelson Robinson - Algebra - 1874 - 338 pages
...divisor. IV. Multiply the divisor thus completed by the last figure of the root ; subtract the product from the dividend; and to the remainder bring down the next period for a new diindend. V. Double the right-hand figure of the last complete divisor for a new divisor, and continue... | |
 | Horatio Nelson Robinson - Arithmetic - 1875 - 462 pages
...complete divisor ; multiply the complete divisor by the trial figure in the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Multiply the last figure of the last complete divisor by 2 and add the product to 10 times... | |
 | Horatio Nelson Robinson - Algebra - 1875 - 430 pages
...complete divisor ; multiply the complete divisor by the trial figure in the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Take the last complete divisor, doubling its right-hand figure, for a new trial divisor,... | |
 | Lorenzo Fairbanks - 1875 - 468 pages
...divisor. IV. Multiply the divisor thus obtained by the digit of the root last found: subtract the product from the dividend, and to the remainder' bring down the next period for a new dividend. V. Double the part of the root already found, for a new divisor, and proceed as before ;... | |
 | Thomas Henderson - 1876 - 114 pages
...square of the last figure. Multiply the complete divisor by the last root figure, subtract the product from the dividend, and to the remainder bring down the next period, if any, or add three cyphers, for a new dividend. To the last complete divisor add the two numbers... | |
 | Joseph Ray - Arithmetic - 1877 - 404 pages
...divisor. P«c. •» 4. Multiply the complete divisor by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root found, for a new trial divisor, and continue the operation in the... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
