| Shelton P. Sanford - Arithmetic - 1872 - 402 pages
...TRUE DIVISOR. IV. Multiply the TRUE DIVISOR by the second figure of the root, subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend. V. Double the root already found for a NEW TRIAL DIVISOE, 5625(75 An, 49 145)725 725 continue... | |
| Henry Beadman Bryant, Emerson Elbridge White, C. G. Stowell - Business mathematics - 1872 - 576 pages
...of the last root figure, and find their sum, calling it the subtraliend. 7. Subtract the subtrahend **from the dividend, and to the re•mainder bring down the next period for a new** dividend, ivilh which proceed as before till the required root be found. NOTES. — 1. When any dividend... | |
| Ezra S. Winslow - Business mathematics - 1872 - 256 pages
...the divisor, as it now stands, by the figure last placed in the quotient, and subtract the product **from the dividend, and to the remainder bring down the next period for a** dividend, as before. 5. Multiply the quotient (now consisting of 3 figures) by 2, as before, and take... | |
| Elias Loomis - Algebra - 1873 - 396 pages
...Multiply the divisor thus increased by the last figure of the root ; subtract the product from Hie **dividend, and to the remainder bring down the next period for a new** dividend. 6th. Take three hundred times the square of the whole root now found for a new trial divisor,... | |
| Horatio Nelson Robinson - Algebra - 1874 - 338 pages
...divisor. IV. Multiply the divisor thus completed by the last figure of the root ; subtract the product **from the dividend; and to the remainder bring down the next period for a new** diindend. V. Double the right-hand figure of the last complete divisor for a new divisor, and continue... | |
| Horatio Nelson Robinson - Arithmetic - 1875 - 462 pages
...complete divisor ; multiply the complete divisor by the trial figure in the root, subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend. V. Multiply the last figure of the last complete divisor by 2 and add the product to 10 times... | |
| Horatio Nelson Robinson - Algebra - 1875 - 430 pages
...complete divisor ; multiply the complete divisor by the trial figure in the root, subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend. V. Take the last complete divisor, doubling its right-hand figure, for a new trial divisor,... | |
| Lorenzo Fairbanks - 1875 - 468 pages
...divisor. IV. Multiply the divisor thus obtained by the digit of the root last found: subtract the product **from the dividend, and to the remainder' bring down the next period for a new** dividend. V. Double the part of the root already found, for a new divisor, and proceed as before ;... | |
| Thomas Henderson - 1876 - 114 pages
...square of the last figure. Multiply the complete divisor by the last root figure, subtract the product **from the dividend, and to the remainder bring down the next period,** if any, or add three cyphers, for a new dividend. To the last complete divisor add the two numbers... | |
| Joseph Ray - Arithmetic - 1877 - 404 pages
...divisor. P«c. •» 4. Multiply the complete divisor by the last figure of the root; subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend. 5. Double the whole root found, for a new trial divisor, and continue the operation in the... | |
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