| Horatio Nelson Robinson - Algebra - 1863 - 432 pages
...complete divisor ; multiply the complete divisor Ъу the trial figure in the root, subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend. V. Take the last complete divisor, doubling its right-hand figure, for a new trial divisor,... | |
| Elias Loomis - Algebra - 1864 - 386 pages
...figure. 5. Multiply the divisor thus increased by the last figure of the root; subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend. 6. Take three hundred times the square of the whole root now found for a new trial divisor,... | |
| Charles Davies - Arithmetic - 1865 - 372 pages
...divisor. IV. Multiply the divisor thus increased, by the last JigKt of the root ; subtract the product **from the dividend, and to the remainder bring down the next period for a** neic dividend. V. Double the whole root thus found, for a new trial divisor, and continue the operation... | |
| W H. Wingate - 1865 - 150 pages
...trial divisor and the last figure in the root — add these three results for a subtrahend which take **from the dividend, and to the remainder bring down the next period,** and proceed as before. EXAMPLE. — Find the cube root of 4.410944. 4.410944(164 1гхЗ=3 Trial Divisor... | |
| Joseph Ray - Algebra - 1852 - 420 pages
...divisor. 4th. Multiply the divisor thus increased by the last figure of the root, sulitract the product **from the dividend, and to the remainder bring down the -next period for a new** dividend. f>th. Double the whole root already found for a new divisor, and ccn- ^ tinue the operation... | |
| Joseph Ray - Algebra - 1866 - 252 pages
...divisor. 4. Multiply the divisor, thus increased, by the last figure of the root; subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend. 5. Double the whole root already found for a new divisor, and continue the operation as before,... | |
| Joseph Ray - Algebra - 1866 - 420 pages
...divisor. 4th. Multiply the complete divisor by the last figure of the root, and subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend, and so proceed until all the periods arc brought down. Extract the cube root of the following... | |
| Joseph Ray - Algebra - 1866 - 252 pages
...Multiply the divisor, thus increased, by the last figure of the root; subtract the product from tJic **dividend, and to the remainder bring down the next period for a new** dividend. 5. Double the whole root already found for a new divisor, and continue the operation as before,... | |
| Ezra S. Winslow - Business mathematics - 1867 - 232 pages
...the divisor, as it now stands, by the figure last placed in the quotient, and subtract the product **from the dividend, and to the remainder bring down the next period for a** dividend, as before. 5. Multiply the quotient (now consisting of 3 figures) by 2, as before, and take... | |
| Robert Wallace - 1870 - 164 pages
...divisor. Multiply the complete divisor by the last figure of the root thus obtained, subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend. Double the whole root already found for a partial divisor, and continue the operation, as... | |
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