 | Horatio Nelson Robinson - Algebra - 1863 - 432 pages
...complete divisor ; multiply the complete divisor Ъу the trial figure in the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Take the last complete divisor, doubling its right-hand figure, for a new trial divisor,... | |
 | Elias Loomis - Algebra - 1864 - 386 pages
...figure. 5. Multiply the divisor thus increased by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 6. Take three hundred times the square of the whole root now found for a new trial divisor,... | |
 | Charles Davies - Arithmetic - 1865 - 372 pages
...divisor. IV. Multiply the divisor thus increased, by the last JigKt of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a neic dividend. V. Double the whole root thus found, for a new trial divisor, and continue the operation... | |
 | W H. Wingate - 1865 - 150 pages
...trial divisor and the last figure in the root — add these three results for a subtrahend which take from the dividend, and to the remainder bring down the next period, and proceed as before. EXAMPLE. — Find the cube root of 4.410944. 4.410944(164 1гхЗ=3 Trial Divisor... | |
 | Joseph Ray - Algebra - 1852 - 422 pages
...divisor. 4th. Multiply the divisor thus increased by the last figure of the root, sulitract the product from the dividend, and to the remainder bring down the -next period for a new dividend. f>th. Double the whole root already found for a new divisor, and ccn- ^ tinue the operation... | |
 | Joseph Ray - Algebra - 1866 - 250 pages
...divisor. 4. Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the operation as before,... | |
 | Joseph Ray - Algebra - 1866 - 420 pages
...divisor. 4th. Multiply the complete divisor by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, and so proceed until all the periods arc brought down. Extract the cube root of the following... | |
 | Joseph Ray - Algebra - 1866 - 252 pages
...Multiply the divisor, thus increased, by the last figure of the root; subtract the product from tJic dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the operation as before,... | |
 | Ezra S. Winslow - Business mathematics - 1867 - 232 pages
...the divisor, as it now stands, by the figure last placed in the quotient, and subtract the product from the dividend, and to the remainder bring down the next period for a dividend, as before. 5. Multiply the quotient (now consisting of 3 figures) by 2, as before, and take... | |
 | Robert Wallace - 1870 - 164 pages
...divisor. Multiply the complete divisor by the last figure of the root thus obtained, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Double the whole root already found for a partial divisor, and continue the operation, as... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
