 | Horatio Nelson Robinson - Arithmetic - 1859 - 352 pages
...the complete divisor. V. Multiply the complete divisor by the trial figure, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. VI. Add the square of the last figure of the root, the last term in column II, and the complete... | |
 | James Bates Thomson - Arithmetic - 1860 - 440 pages
...; multiply- the divisor thus completed by the figure last placed in the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new partial divisor, divide, <£c., as before, and... | |
 | Horatio Nelson Robinson - Arithmetic - 1860 - 444 pages
...the complete divisor. V. Multiply the complete divisor by the trial figure ; subtract the. product from the dividend, and to the remainder bring down the next period for a new dividend. VI. Add the square of the last figure of the root, the last term in column II, and the complete... | |
 | Daniel Adams - Arithmetic - 1861 - 452 pages
...the root (the breadth of the additions), and subtract the contents of the additions thus obtained, from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new divisor, and continue the operation as before,... | |
 | Charles Davies - Arithmetic - 1861 - 496 pages
...divisor : IV. Multiply the divixor thus increased, by the last figure of the root j subtract the product from the dividend, and to the remainder bring down the next period for a new dividend: V. Double the whole root thus found, for a new trial divisor, -and continue the operation... | |
 | Charles Davies - Algebra - 1861 - 322 pages
...divisor. IV. Multiply the divisor, thus augmented, by the lastfyurt of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. But if any of the products should be greater than the dividend, diminish the last figure... | |
 | John Flint (inspector of schools.) - 1862 - 152 pages
...divisor. Multiply the divisor thus completed by the figure of the root last found, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend, and for a new divisor add the figure of the root last found, with which proceed as before,... | |
 | Elias Loomis - Algebra - 1862 - 312 pages
...divisor. 4. Multiply the divisor, thus increased, by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. If the product should be greater than the dividend, diminish the last figure of the root.... | |
 | James Bates Thomson - Arithmetic - 1862 - 436 pages
...; multiply the divisor thus completed by the figure last placed in the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new partial divisor, divide, &c., as before, and... | |
 | Charles Davies - Arithmetic - 1863 - 346 pages
...divisor: IV. Multiply the divisor thus increased, by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend : NOTES. — 1. The left-hand period may contain but one figure ; each of the others will... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
