| Elias Loomis - Algebra - 1855 - 356 pages
...divisor. 4. Multiply the divisor thus increased by the last figure of tli& root ; subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend. 5. Double the whole root now found for a new divisor, and continue the operation, as before,... | |
| George Roberts Perkins - Arithmetic - 1855 - 382 pages
...for its next term. Multiply this term by the last found figure of the root, and subtract the product **from the dividend, and to the remainder bring down the next period for a NEW** DIVIDEND. Proceed as before until all the periods have been brought down. NOTE 1. — When any dividend... | |
| Roswell Chamberlain Smith - Arithmetic - 1856 - 344 pages
...quotient figure ; then ndd these three results together for a subtrahend. 17. Subtract the subtrahend **from the dividend, and to the remainder bring down the next period for a new** dividend, with which proceed as before, and so on till all the periods are brought down.* 18. NOTE.... | |
| Charles Guilford Burnham - Arithmetic - 1857 - 328 pages
...write the cube of the last quotient figure, and call their sum the subtrahend. Subtract the subtrahend **from the dividend, and to the remainder bring down the next period, for a new** dividend, and proceed as before, till the work is finished. EXAMPLES. 2. What is the cube root of 1906624... | |
| Benjamin Greenleaf - Arithmetic - 1857 - 452 pages
...for a true divisor. Multiply the true divisor by the last figure of the root : subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend. To the last true divisor and the number immediately over it, add the square of the last root... | |
| Charles Guilford Burnham - 1857 - 336 pages
...cube of the last quotient figure, and call their sum the subtrahend. Subtract the subtrahend from tlte **dividend, and to the remainder bring down the next period, for a new** dividend, and proceed as before, till the work is finished. EXAMPLES. 2. What is the cube root of 1906624... | |
| Benjamin Greenleaf - Arithmetic - 1858 - 470 pages
...for a true divisor. Multiply the true divisor by the last figure of the root; subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend. Multiply the square of (lie root figures already found by 3, and to the product annex two... | |
| Thomas William Silloway - Carpentry - 1858 - 236 pages
...the right hand of the divisor. Multiply the divisor by the last quotient-figure, subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend, 4th, Double the quotient already found for a partial divisor, and from these find the next... | |
| Elias Loomis - Algebra - 1858 - 394 pages
...figure. 5. Multiply the divisor thus increased by the last figure of the root ; subtract the product **from the dividend, and to the remainder bring down the next period for a new** dividend. 6. Take three hundred times the square of the whole root now found for a new trial divisor,... | |
| Benjamin Greenleaf - Arithmetic - 1858 - 458 pages
...for a true divisor. Multiply the true divisor by the last figure of the root : subtract the product **from the dividend, and to the remainder bring down the next period** far a new dividend. To the last true divisor and the number immediately over it, add the square of... | |
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