 | Oxford and Cambridge schools examination board - 1874 - 298 pages
...which the point of contact is a focus. Analytical Conic Sections. 5. Investigate an expression for the area of a triangle in terms of the coordinates of its angular points ; and thence deduce the equation of a straight line joining two given points. 6. Shew how to transform... | |
 | J. G - 1878 - 408 pages
...the straight line is to be bisected, then m=n, and we hare 3. To find an analytical expression for the area of a triangle in terms of the co-ordinates of its angular points. Area = tfx,y 1 -x 1 y t + x^y* - z a y s + a^y „ - x t y l }. To remember this formula, observe that... | |
 | Charles Smith - Conic sections - 1883 - 452 pages
...points (2, 1), (5, 4), (4, 7) and (1, 4) are the angular points of a parallelogram. * 6. To express the area of a triangle in terms of the co-ordinates of its angular points. Let the co-ordinates of the angular points A, B, G be x i> Vi> x *> &; and «v y, respectively. oK... | |
 | Charles Smith - Conic sections - 1883 - 388 pages
...points (2, 1), (5, 4), (4, 7) and (1, 4) are the angular p'oints of a parallelogram. 6. To express the area of a triangle in terms of the co-ordinates of its angular points. Let the co-ordinates of the angular points A, B, C be *i, Vi, x 2, y2, and x », V, respectively. MX... | |
 | George Hale Puckle - Conic sections - 1887 - 396 pages
...the perpendicular from the point (x = 3, y = 5) on the line (3i/ - 7o: + 9 = 0). , 3x5-7x3+9 3 53 1 . To find the area of a triangle in terms of the coordinates of the angular points, the axes being rectangular. Let the 'three points be (xy), (x'y'), (x'y"). The... | |
 | Isaac Todhunter - Conic sections - 1888 - 376 pages
...sections have the same excentricity. Area of a Polygon. 301. In Art. 11 we have given an expression for the area of a triangle in terms of the co-ordinates of its angular points: we shall now investigate the corresponding expression for the area of any polygon. Let the angular... | |
 | John Casey - Geometry, Analytic - 1893 - 604 pages
...*V" ~ *"'y', or (x'y" - x"^} + (x"y m - x"'y") + (x'"y' - x'y'"} = 0. 8. The Lemma of § 7 enables us to find the area of a triangle in terms of the co-ordinates of its summits. For, if any point 0 within the triangle he taken as the origin of rectangular axes, and the... | |
 | Charles Smith - Conic sections - 1893 - 370 pages
...four points (2, 1), (5, 4), (4, 7) and (1, 4) are the angular points of a parallelogram. 6. To express the area of a triangle in terms of the co-ordinates of its angular points. Let the co-ordinates of the angular points A, B, G be a i> y» ^ V»> and *8> y* respectively. OK M... | |
 | Edinburgh Mathematical Society - Mathematics - 1893 - 352 pages
...and on transformation to the other systems we readily obtain the above expressions. 4. To find tlie area of a, triangle in terms of the co-ordinates of its angular points. (1) Independently of the corresponding expression in Cartesians. If A' denote the area, since twice... | |
 | Charles Smith - Conic sections - 1894 - 456 pages
...four points (2, 1), (5, 4), (4, 7) and (1, 4) are the angular points of a parallelogram. 6. To express the area of a triangle in terms of the co-ordinates of its angular points. Let the co-ordinates of the angular points A, B, C be x i> Vv x vy*> and x » y> respectively. Draw... | |
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To find the area of a triangle, in terms of the co-ordinates of its angular points; 
