| Benjamin Greenleaf - Arithmetic - 1844 - 208 pages
...days, as before. Hence the following RULE. Multiply each payment by the time at which it is due, then divide the sum of the products by the sum of the payments, and the quotient wiU be the true time required. 8. John Smith owes a merchant, in Boston, $ 1000, $250... | |
| Charles Davies - Arithmetic - 1846 - 370 pages
...due, equal to ? Hence, to find the mean time, Multiply each payment by the time before it becomes due, and divide the sum of the products by the sum of the payments : the quotient will be the mean time. EXAMPLES. 1 . B owes A $600 : $200 is to be paid in two months, $200 in four... | |
| Arithmetic - 1846 - 258 pages
...at several different times. RULE. — (2) Multiply each payment by the time at which it is due; then divide the sum of the products by the sum of the payments, and the quotient will be the equated time. Questions. — l.What is the use of the rule of Equation... | |
| Popular encyclopedia - 1846 - 886 pages
...given for this purpose is as follows ; — Multiply each sum by the time at which it is due ; then divide the sum of the products by the sum of the payments, and the quotient will he the time required. Thus, for example, A owes B £190, to be paid as follows... | |
| Charles Davies - Arithmetic - 1847 - 368 pages
...payments.) Hence, to find the mean time, ' .• , ' Multiply each payment by ihe time before it becomes due, and divide the sum of the products by the sum of the payments : the quotient will be the mean time. EXAMPLES. .'•, 1. B owes A $600 : $200 is to be paid in two months, $200 in... | |
| Charles Davies - Arithmetic - 1848 - 372 pages
...time fer the payment of the whole ? We here multiply each sum by the time at which it becomes due, and divide the sum of the products by the sum of the payments. OPERATION. 200x2= 400 200x4= 800 200x6 = 1200 6JOO )24|00 w Ans. 4 months. 2. A merchant owes $600,... | |
| Thomas Rainey - Arithmetic - 1849 - 320 pages
...Multiply the sum of each payment by its time, add the several payments: then, add their products ; and divide the sum of the products, by the sum of the payments. The several periods of time must be of the same denomination ; tither days, months, or y'ars, separately... | |
| James Haddon - Arithmetic - 1849 - 144 pages
...payments, due at different times, should be paid at once. BULE. Multiply each payment by its time, and divide the sum of the products by the sum of the payments. PARTNERSHIP. Partnership or Fellowship is a method of finding the shares in the profit or loss of several... | |
| Charles Davies - Arithmetic - 1850 - 412 pages
...the payments.) Hence, to find the mean time, Multiply each payment by the time before it becomes due, and divide the sum of the products by the sum of the payments : the quotient will be the mean time. EXAMPLES. 1. B owes A $600: $200 is to be paid in two months, $200 in four months,... | |
| Charles Guilford Burnham - 1850 - 350 pages
...---15=5 months, the answer. Hence the RULE. Multiply each payment by the time when it becomes due, and divide the sum of the products by the sum of the payments, and the quotient will be the time required. 2. A merchant has owing him $420, to be paid as follows... | |
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