 | Education - 1902 - 780 pages
...following and prove 'division one of them : if two parallels are cut by a transversal . . . 2 Prove that in the same circle or in equal circles equal chords are equally distant from the center. 3 Prove that if a line is drawn through two sides of a triangle parallel to the third side,... | |
 | Education - 1902 - 880 pages
...and prove •division one of them : if two parallels are cut by a transversal . . . 2 Prove that in the same circle or in equal circles equal chords are equally distant from the center. 3 Prove that if a line is drawn through two sides of a triangle parallel to the third side,... | |
 | Alan Sanders - Geometry - 1903 - 396 pages
...of these arcs, prove that it is perpendicular to AB and bisects it. PROPOSITION X. THEOREM 283. In the same circle or in equal circles equal chords are equally distant from the center; and conversely, chords that are equally distant from the center are equal. Let AB and CD be... | |
 | George Albert Wentworth - Geometry - 1904 - 496 pages
...and bisects the arcs of the chord. ARCS, CHORDS, AND TANGENTS. 83 PROPOSITION VI. THEOREM. 249. In the same circle or in equal circles, equal chords are equally distant from the centre. CONVERSELY : Chords equally distant from the centre are equal. Let AB and CF be equal chords of the... | |
 | Edward Rutledge Robbins - Geometry, Plane - 1906 - 268 pages
...(219). .-. OP is -L to AB at its midpoint (?) (70). IV. Arc AX = arc BX (?) (206). QED 221. THEOREM. In the same circle (or in equal circles) equal chords are equally distant from the center. Given : O o ; chord AB = chord CD, and distances OE and OF. To Prove : OE = OF. Proof : Draw... | |
 | Wisconsin. Department of Public Instruction - Education - 1906 - 124 pages
...line joining the center of two intersecting circles bisects their common chord at right angles. 48. In the same circle or in equal circles, equal chords are equally distant from the center; and of two unequal chords, the shorter is farther from the center. 49. Converse of 48. 50.... | |
 | Edward Rutledge Robbins - Geometry - 1907 - 428 pages
...(219). .-. OP is .L to AB at its midpoint (?) (70). IV. Arc AX = arc UK (?) (206). QED 221. THEOREM. In the same circle (or in equal circles) equal chords are equally distant from the center. Given : OO ; chord AB = chord CD, and distances OE and OF. To Prove : OE = OF. Proof : Draw... | |
 | Webster Wells - Geometry - 1908 - 336 pages
...BC. (§ 155) 5. Again, ZAOD = ^BOD. (§41,2) 6. Then, arc AD = arc BD. (?) PROP. IX. THEOREM 164. In the same circle, or in equal circles, equal chords are equally distant from the centre. Draw a O with centre at O ; draw equal chords AB and CD. Draw lines OE and OF± AB and (7Z>, respectively,... | |
 | Webster Wells - Geometry, Plane - 1908 - 208 pages
...BC. (§ 155) 5. Again, ZAOD = ^BOD. (§41,2) 6. Then, arc AD = arc BD. (?) PROP. IX. THEOREM 164. In the same circle, or in equal circles, equal chords are equally distant from the centre. Draw a O with centre at O ; draw equal chords AB and CD. Draw lines OE and OF± AB and CD, respectively,... | |
 | Elmer Adelbert Lyman - Geometry - 1908 - 364 pages
...bisector of CD is the locus of all points equally distant from C and D. ... etc. THEOREM IX 258. In the same circle or in equal circles, equal chords are equally distant from the center; and of two unequal chords, the slwrter is farther from the center. Given: CD = EF and AB<EF... | |
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In the same circle, or in equal circles, equal chords are equally distant from the centre ; and of two unequal chords, the less is at the greater distance from the centre. 
