 BK, it is demonstrated that the parallelogram CL is equal to the square HC. Therefore the whole square BDEC is equal to the two squares GB, HC ; and the square BDEC is described upon the straight line BC, and the squares GB, HC upon BA, AC.  Elements of Geometry: With Notes - Page 185by John Radford Young - 1827 - 208 pagesFull view - About this book
 | Euclides - 1834 - 518 pages
...therefore the whole angle DBA is equal * to the whole FBC : and because the two sides AB, BD are equal t to the two FB, BC, each to each, and the angle DBA...therefore the parallelogram BL is equal to the square GB. In the same manner, by joining AE, BK, it can be demonstrated, that the parallelogram CL is equal to... | |
 | John Playfair - Geometry - 1836 - 148 pages
...triangle FBC, because these also are upon the same base BF, and between the same parallels BF, CG. But the doubles of equals are equal to one another...therefore the parallelogram BL, is equal to the square BG ; and in the same manner, by joining AE, BK, it is demonstrated that the parallelogram CL is equal... | |
 | Euclid, James Thomson - Geometry - 1837 - 410 pages
...same base FB, and between the same parallels FB, GC. But the doubles of equals are equal (I. ax. 6.) to one another : therefore the parallelogram BL is equal to the square GB. In the same manner, by joining AE, BK, it is demonstrated that the parallelogram CL is equal to the... | |
 | Euclides - 1838 - 264 pages
...the triangle FBC, because these also are upon the same base FB, and between the same parallels »6 Ax FB, GC : but the doubles of equals are equal* to one...therefore the parallelogram BL is equal to the square GB. In the same manner, by drawing AE, BK, it can be demonstrated, that the parallelogram CL is equal to... | |
 | Euclid - Geometry - 1845 - 218 pages
...also are upon the same base FB, and between the same parallels FB, GC. t 31. ]. tHyp. 30 Def. s < AX. But the doubles of equals are equal § to one another;...demonstrated, that the parallelogram CL is equal to the squane HC ; 1 2 AX. Therefore the whole square BDEC is equal IT to the two squares GB, HC ; and the... | |
 | Euclid, James Thomson - Geometry - 1845 - 382 pages
...same base FB, and between the same parallels FB, GC. But the doubles of equals are equal (I. ax. 6) to one another : therefore the parallelogram BL is equal to the square GB. In the same manner, by joming AE, BK, it would be demonstrated that the parallelogram CL is equal to... | |
 | Euclides - 1846 - 292 pages
...the triangle FBC, because they are upon the same base FB, and between the same parallels FB, GC ; and the doubles of equals are equal to one another ; therefore...parallelogram BL is equal to the square GB : And, in like manner, by joining AE, BK, it may be demonstrated, that the parallelogram CL is equal to the square... | |
 | John Playfair - Euclid's Elements - 1849 - 332 pages
...same base- FB, and between the same parallels FB, GC. Now the doubles of equals are equal (6. Ax.) to one another ; therefore the parallelogram BL is equal to the square GB : And in the same mannw, by joining AE, BK, it is demonstrated that the parallelogram CL is equal to the square HC. Therefore,... | |
 | Euclides - 1852 - 152 pages
...upon the same base FB, and between the same parallels FB, GC. But the doubles of equals B are equal h to one another: Therefore the parallelogram BL is...same manner, by joining AE, BK it is demonstrated, iv. 1. xli. 1. 6 Ax. BOOKJ. that the parallelogram CL is equal to the square HC ; Therefore the whole... | |
 | Euclides - Geometry - 1853 - 176 pages
...the same base fb, and between the same parallels fb, gC. But the doubles of equals are equal (6 ax.) to one another : therefore the parallelogram. bl is...ae, bk, it is demonstrated, that the parallelogram С l is equal to the square h С ; therefore the whole square bde С is equal to the two squares gb,... | |
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