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" To find the solidity of a hyperbolic conoid, or otherwise called a hyperboloid. RULE. To the square of the radius of the base, add the square of the diameter... "
A Series on Elementary and Higher Geometry, Trigonometry, and Mensuration ... - Page 219
by Nathan Scholfield - 1845
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Elementary and Practical Instructions on the Science of Railway Construction

Sir Rowland Macdonald Stephenson - Railroads - 1869 - 446 pages
...weight 23-644 oz. PROBLEM IX. To find the solidity of a spherical segment. RULE. — To three times the square of the radius of the base, add the square of the height ; multiply the sum by the height, and the product again by •5236. 1. Required the content...
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Explanatory mensuration for the use of schools

Alfred Hiley - 1871 - 184 pages
...find the volume, when the radius of the base and the height of the segment are given. To three times the square of the radius of the base, add the square of the height ; multiply the sum by the height, and this product by -JJ-. . (2) To find the volume, when the...
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The naval architect's and shipbuilder's pocket book of formulę [&c.].

Clement Mackrow - 1879 - 558 pages
...multiplied by -3927 will be the solidity. 17. To find the solidity of a hyperboloid. (Fig. 99.) FIG. 99. RULE. — To the square of the radius of the base add the square of the diameter at the middle between the base and the vertex ; this sum multiplied by the altitude, and the product...
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Explanatory Mensuration

Alfred Hiley - 1879 - 228 pages
...find the volume, when the radius of the base and the height of the segment are given. To three times the square of the radius of the base, add the square of the height ; multiply the sum by the height, and this product by |-j-. (2) To find the volume, when the...
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The Architect's and Builder's Pocket-book

Frank Eugene Kidder - Architecture - 1886 - 640 pages
...the base by half Fig.43 the altitude. To compute the volume of a hyperboloid of revolution (Fig. 44). RULE. — To the square of the radius of the base add the square of the middle diameter; multiply this sum by the height, and the product by 0.5236. To compute the volume...
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A Mathematical Solution Book Containing Systematic Solutions to Many of the ...

Benjamin Franklin Finkel - Mathematics - 1888 - 518 pages
...— F"=^7r(/?2-[-^2)/', where R is the radius of the base, a^the middle diameter, and h the altitude. Rule. — To the square of the radius of the base add the square of the middle diameter between the base and the vertex; and this sum multiplied by the altitude, and the product...
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The Architect's and Builder's Pocket-book of Mensuration, Geometry ...

Frank Eugene Kidder - Architecture - 1892 - 1032 pages
...base by half Fig.43 the altitude. To compute the volume of it hyperbolotil of revolution (Fig. 44). RULE. — To the square of the radius of the base add the square of the middle diameter; multiply this sum by the height, and the product by 0.5236. TII compute the volume...
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The Architect's and Builder's Pocket-book of Mensuration, Geometry ...

Frank Eugene Kidder - Architecture - 1892 - 1058 pages
...by half Fig.43 the altitude. To compute the volume of « hyptrboloiil of revolution (Fig. 44). RULK. —To the square of the radius of the base add the square of the middle diameter; multiply this sum by Hie height, and the product by 0.5230. Fig.44 Tn compute the...
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Hodgson's Estimator and Contractor's Guide for Pricing Builder's Work ...

Frederick Thomas Hodgson - Architecture, Domestic - 1904 - 370 pages
...05236=63774.48. Ans. OF HYPERBOLOIDS AND HYPERBOLIC CONOIDS Problem XVI. — To find the solidity of a hyperboloid. Rule. — To the square of the radius' of the base, as, add the square of the middle diameter, mr; multiply this sum by the height, sf, and the product...
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Henley's Encyclopędia of Practical Engineering and Allied Trades: A ...

Joseph Gregory Horner - Engineering - 1909 - 560 pages
...the surface is called the height. To find the volume of a segment of a sphere : — To three times the square of the radius of the base add the square of the height, then multiply this sum by the height, and the product by '5236. To find the area of the surface...
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