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" If any partial dividend will not contain the divisor, place a cipher in the quotient, and bring down the next figure of the dividend, and divide as before. "
Daboll's Complete Schoolmaster's Assistant: Being a Plain Comprehensive ... - Page 44
by Nathan Daboll, David Austin Daboll - 1849 - 249 pages
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New Complete Arithmetic on the Inductive Method: With Parallel Mental and ...

James William Nicholson - Arithmetic - 1885 - 348 pages
...brought down. When one of the partial dividends is less than the divisor, write 0 for the next figure of the quotient, and bring down the next figure of the dividend. PROOF. — The same as in short division. After all the figures of the dividend have been brought down and divided,...
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Caldwell's Practical Arithmetic ...

M. P. Caldwell - Arithmetic - 1883 - 198 pages
...at any time, after bringing down a figure, the nwrri'ber thus formed will not contain the divisor, place a cipher in the quotient, and bring down the next figure and divide as before. 54 7574(140 54 217 216 14 Remainder. 2. Divide 11578 by 14. Ans. 827 3. Divide...
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Robinson's Progressive Practical Arithmetic: Containing the Theory of ...

Horatio Nelson Robinson - 1888 - 372 pages
...dividend Jiave been brought down and divided. V. If any partial dividend will not contain the divisor, place a cipher in the quotient, and bring down the next figure of the dividend, and divide as before. VL If there be a remainder after dividing all the figures of the dividend, it...
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An Advanced Arithmetic, Theoretical and Practical

James William Nicholson - Arithmetic - 1889 - 408 pages
...down. V. When one of the partial dividends is less than the divisor, write 0 for the next figure of the quotient, and bring down the next figure of the dividend. ^ PROOF. — Multiply the quotient by the divisor, and to the product add the remainder, if any ; the result...
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Robinson's New Practical Arithmetic for Common Schools and Academies

Horatio Nelson Robinson - Arithmetic - 1892 - 428 pages
...which is 0, making 20, for the second partial dividend. Then, since 23 is contained in 20 no times, we place a cipher in the quotient, and bring down the next figure of the dividend, making a third partial dividend, 207 ; 23 is contained in 207, 9 times; multiplying and subtracting...
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Robinson's New Practical Arithmetic for Common Schools and Academies

Horatio Nelson Robinson - Arithmetic - 1892 - 428 pages
...dividend have been brought down and divided. V. If any partial dividend will not contain the divisor, place a cipher in the quotient, and bring down the next figure of the dividend, and divide as before. VI. If there is a remainder after dividing all the figures of the dividend, it...
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For fourth and fifth grades

George Edward Atwood - Arithmetic - 1894 - 214 pages
...the figures of the dividend have been used. If any new dividend does not contain the divisor, write a cipher in the quotient and bring down the next figure of the dividend. If there is a remainder after the last division, write it over the divisor at the right of the quotient....
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For 6th-8th grade

George Edward Atwood - Arithmetic - 1899 - 392 pages
...the figures of the dividend have been used. If any new dividend does not contain the divisor, write a cipher in the quotient and bring down the next figure of the dividend. FACTORING. 47. An Exact Divisor of a number is a number that will divide it without a remainder. 48....
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A Textbook of Electric Lighting and Railways, Volume 1

International Correspondence Schools - Electric lighting - 1901 - 630 pages
...3 9 7 2 8.0 0 0 ( 6 3 0.6 0 3+ Ans. 378 1 92 189 380* 378 200 189 *63 is not contained in 38, so we place a cipher in the quotient and bring down the next figure in the dividend, which is a cipher that has been annexed, making a new dividend of 380. 63 is contained...
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A Textbook on Sheet-metal Pattern Drafting, Volume 1

Metal-work - 1901 - 548 pages
...write the next figure of the dividend, making 13. Now, 39 is not contained in 13; therefore, put 0 in the quotient and bring down the next figure of the dividend, making 132. The divisor 39 is contained in 132, 3 times; put 3 in the quotient, and subtract 39 X 3,...
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