| Henry James Castle - Surveying - 1856 - 185 pages
...angles are the exterior angles of an irregular polygon ; and as the sum of all the interior angles are **equal to twice as many right angles, as the figure has sides,** wanting four ; and as the sum of all the exterior, together with all the interior angles, are equal... | |
| Cambridge univ, exam. papers - 1856
...Prove that all the internal angles of any rectilineal figure, together with four right angles, are **equal to twice as many right angles as the figure has sides;** and that all the external angles are together equal to four right angles. In what sense are these propositions... | |
| Elias Loomis - Conic sections - 1857 - 226 pages
...angles of a polygon, is equal to twice as many right angles, wanting four, as the figure has sides. **Let ABCDE be any polygon ; then the sum of all its...B, C, D, E is equal to twice as many right angles,** wanting four, as the figure has sides (see next page). For, from any point, F, within it, draw lines... | |
| Adrien Marie Legendre - Geometry - 1857 - 444 pages
...equal to twice as many right angles as the polygon has sides. Again, the sum of all the interior angles **is equal to twice as many right angles as the figure has sides, less four right angles** (p. 26). Hence, the interior angles plus four right angles, is equal to twice as many right angles... | |
| William Mitchell Gillespie - Surveying - 1857 - 538 pages
...proposition of Geometry, that in any figure bounded by straight lines, the sum of all the interior angles **is equal to twice as many right angles, as the figure has sides less** two ; since the figure can be divided into that number of triangles. Hence this common rule. " Calculate... | |
| Elias Loomis - Conic sections - 1858 - 234 pages
...angles of a polygon, is equal to twice as many right angles, wanting four, as the figure has sides. **Let ABCDE be any polygon ; then the sum of all its...B, C, D, E is equal to twice as many right angles,** wanting four, as the figure has sides (see next page). For, from any point, F, within it, draw lines... | |
| W. Davis Haskoll - Civil engineering - 1858 - 324 pages
...and in an irregular polygon they may be all unequal. The interior angles of a polygon are together **equal to twice as many right angles as the figure has sides, less four.** On this is based the theory of the traverse, of which further explanation will be given in another... | |
| Charles Hutton - Mathematics - 1860 - 1022 pages
...Hence it lotIons that the sum of all the inward angles of the polygon alone, A -f- В — -f. D -f. **E, is equal to twice as many right angles as the figure has** side*, «am¡ng the said tour right angles- Q. !•'- D. THEOREM xx. When every side of any figure... | |
| John Henry Robson - 1880
...proved that " All the Interior angles of any Rectilineal figure, "together with four right angles, are **equal to "twice as many right angles as the figure has " sides."** If, therefore, we suppose the polygon to have n sides, All its interior angles + 4.90 .= 272.90 . -.... | |
| Science - 1880 - 668 pages
...XXVI. of the syllabus, that the interior angles of any polygon, together with four right angles, are **equal to twice as many right angles as the figure has sides.** In the new notation we would say that the sum of the interior angles of the polygon is equal to a number... | |
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