 | Charles Davies, Adrien Marie Legendre - Geometry - 1885 - 538 pages
...eight right angles, or $ of one right angle. Cor. 4. In any equiangular polygon, any interior angle is equal to twice as many right angles as the figure has sides, less four right angles, divided by the mimber of angles. PROPOSITION XXVII. THEOREM. The sum of the exterior angles of a polygon... | |
 | 1885 - 608 pages
...Show that the sum of the interior angles of any rectilineal figure together witli four right angles, is equal to twice as many right angles as the figure has sides. 5. Prove that the opposite sides and angles of a parallelogram are equal to one another, and that the... | |
 | William Davis Haskoll - Hydrographic surveying - 1886 - 354 pages
...every station on a survey. In any polygon, regular or irregular, the sum of all the interior angles is equal to twice as many right angles as the figure has sides, less four right angles. As observed above, and as may be seen by referring to the figure 52, whether we consider the regular... | |
 | Richard Anthony Proctor - Geometry - 1887 - 202 pages
...produced to meet, the angles formed by these lines, together with eight right angles, are together equal to twice as many right angles as the figure has sides. 139. AP, BP, and CP are the internal bisectors of the angles of the triangle ABC. AP is produced to... | |
 | Bennett Hooper Brough - Mine surveying - 1888 - 366 pages
...accuracy of the survey, as the interior angles of the polygon together with four right angles should be equal to twice as many right angles as the figure has sides. The interior angles of a traverse may be found from the bearings or courses by the following rules... | |
 | E. J. Brooksmith - Mathematics - 1889 - 356 pages
...right angles : that the sum of the angles of any rectilineal figure together with four right angles is equal to twice as many right angles as the figure has sides : and that the sum of the distances of any point from the angular points of the figure is greater than... | |
 | Edward Albert Bowser - Geometry - 1890 - 420 pages
...2 rt. Zs (n — 2) = 2n rt. Zs — 4 rt. Zs. Therefore, the sum of the angles of a polygon is also equal to twice as many right angles as the figure has sides, less four right angles. 149. COR. 2. The sum of the angles of a quadrilateral is equal to two right angles taken (4 — 2)... | |
 | James Hutchins Baker - Logic - 1890 - 244 pages
...case of a particular polygon that the sum of its interior angles, together with four right angles, is equal to twice as many right angles as the figure has sides — and conclude that the law holds good of all polygons. In calculating the terms of a ' Mill's Logic,... | |
 | Edward Mann Langley, W. Seys Phillips - 1890 - 538 pages
...COROLLARY I.— All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. D For any rectl. figure, ABCDE, can be divided into as many As as the figure has sides by drawing st.... | |
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All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 
