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" Prove that parallelograms on the same base and between the same parallels are equal in area. "
A Series on Elementary and Higher Geometry, Trigonometry, and Mensuration ... - Page 44
by Nathan Scholfield - 1845
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Mensuration for Marine and Mechanical Engineers: (second and First Class ...

John William Angles - Measurement - 1919 - 200 pages
...Area of triangle = | x base x perpendicular height = \bh <s— — —— — • —SB^ Triangles on the same base and between the same parallels are equal in area. The line joining the apex of a triangle to the middle point of the opposite side is called a...
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The Teaching of Geometry in Schools: A Report Prepared for the Mathematical ...

Mathematical Association - Geometry - 1923 - 88 pages
...perpendicular and taking the two cases, of which the first is easy and the second hard). (iii) Triangles on the same base and between the same parallels are equal in area (deduced from (ii) since each is given numerically by ?, base x height). (iv) The converse to...
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Electrical Measuring Instruments: Induction instruments, supply meters and ...

Charles Vickery Drysdale, Alfred Charles Jolley - 1924 - 492 pages
...equal to the area of the parallelogram formed by 72 and the induced current i, since parallelograms on the same base and between the same parallels are equal in area. But if the reactance of the shading coil is negligible compared with its resistance i oc /$2...
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Bulletin

Education - 1917 - 964 pages
...in F, and F is joined to B. Prove that the angles BFA. EFA are equal. 3. Prove that parallelograms on the same base and between the same parallels are equal in area. ABCD, AEFG are two parallelograms having a common point at A, and having the vertex E on BC,...
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In Polya's Footsteps: Miscellaneous Problems and Essays, Volume 19

Ross Honsberger - Mathematics - 1997 - 332 pages
...Now, parallelogram PRQiPi has base PR and lies between the parallels PR and AB. Since parallelograms on the same base and between the same parallels are equal in area, another parallelogram of area x would be PRJB determined by a line JRK through R parallel to...
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NDA (National Defence Academy Examination)

934 pages
...other two sides, then the triangle is a right angled triangle. 2.2 Area Properties: (i) Parallelograms on the same base and between the same parallels are equal in area. (ii) The area of a parallelogram is equal to the area of a rectangle on the same base and of...
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Challenge and Thrill of Pre-College Mathematics

V Krishnamurthy, C R Pranesachar - Mathematics - 2007 - 708 pages
...from A to B/ and C/. Prove that XY is parallel to BC. 3.5 SIMILAR TRIANGLES Theorem 27 Parallelograms on the same base and between the same parallels are equal in area. Proof Let ABCD and ABXY be two parallelograms having the same base AB and lying between the same...
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Definitions and Formulae in Mathematics IX & X

Ravi Kumar - Mathematics - 2006 - 152 pages
...and between the same parallels, AQ and DR, then ar (||gm ABCD) = ar (||gm PQRS). Theorem 3. Triangles on the same base and between the same parallels are equal in area, ie, in two AABC and DBC on the same base BC and between the same parallel lines BC and AD, then...
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The Hellenistic Philosophers: Volume 1, Translations of the Principal ...

A. A. Long, D. N. Sedley - Philosophy - 1987 - 352 pages
...Euclid's Elements I 395,13-18 (SVF 2.365, part) Such theorems [ie as the theorem that parallelograms on the same base and between the same parallels are equal in area], Geminus reports, were compared by Chrysippus to the Ideas [cf. 30]. For just as the Ideas encompass...
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Riders in Geometry

Thomas Hadyn Ward Hill - 190 pages
...AB.} THE AREA GROUP OF PROPOSITIONS The fundamental proposition of this section is that parallelograms on the same base and between the same parallels are equal in area. From this we have that triangles on the same base and between the same parallels are equal in...
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