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" Prove that parallelograms on the same base and between the same parallels are equal in area. "
A Series on Elementary and Higher Geometry, Trigonometry, and Mensuration ... - Page 44
by Nathan Scholfield - 1845
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Intermediate Geometry: Being Sections V and VI of "geometry, Theoretical and ...

Walter Percy Workman - Geometry - 1908 - 228 pages
...rectangle is given by the product of the lengths of two adjacent sides 178 Ar.2. — Parallelograms on the same base and between the same parallels are equal in area (Euc. I. So) 184 Ar.3. — If a parallelogram and a triangle be on the same base and between the...
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Mathematical Papers for Admission Into the Royal Military Academy and the ...

Royal Military Academy, Woolwich - Mathematics - 1909 - 456 pages
...Examination may be used in the solution of problems and riders. 1. Prove that two triangles standing on the same base and between the same parallels are equal in area. Hence show that if two triangles have two sides of the one equal to two sides of the other and...
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The Ontario High School Geometry: Theoretical

Alexander H. McDougall - Geometry - 1910 - 316 pages
...nearly; 3. 13-7 sq. cm. nearly; 4. 28'8 sq. cm.; 5. 36 ac. ; 6. 73 ac. nearly. THEOREM 5 Triangles on the same base and between the same parallels are equal in area. X BT Hypothesis.- — ABC, DEC are As on the same base BC and between the same ||s AD, BC. To...
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Industrial Drawing and Geometry: An Introduction to Various Branches of ...

Henry John Spooner - Geometrical drawing - 1911 - 196 pages
...triangles are on the same base and between the same parallels. Euclid (I. 37) proves that all triangles on the same base and between the same parallels are equal in area. Area=l S / r \ q .o O W, 4/ -ea=l 's 9/, h 7C 90. To construct a Rectangle equal in Area to a...
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Practical Geometry and Graphics for Advanced Students

Joseph Harrison, George Albert Baxandall - Geometry, Descriptive - 1913 - 714 pages
...triangle having an area equal to the polygon. This solution is based on the theorem that triangles on the same base and between the same parallels are equal in area. 31. PROBLEM. — To construct a square equal in area to a given rectangle. Determine a mean proportional...
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Report of the Examinations Conducted by the Council of Higher Education ...

Newfoundland Council of Higher Education - 1914 - 228 pages
...along AD and the point B comes to K. Prove that CH\s equal to DK. (8) 6. Assuming that parallelograms, on the same base and between the same parallels, are equal in area, prove that the area of a triangle can be found from the formula : Area = ^ base X height. A point...
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Statistics of Land-grant Colleges and Universities, Volume 2, Issues 17-31

United States. Office of Education - Agricultural colleges - 1917 - 1336 pages
...in F, and F is joined to B. Prove that the angles BFA, EFA are equal. 3. Prove that parallelograms on the same base and between the same parallels are equal in area. ABCD, AEFG are two parallelograms having a common point at A, and having the vertex E on BC,...
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The Money Value of Education, Issues 21-34

Alexander Caswell Ellis - Education - 1917 - 1098 pages
...in F, and F is joined to B. Prove that the angles BFA, EFA are equal. 3. Prove that parallelograms on the same base and between the same parallels are equal in area. ABCD, AEFG are two parallelograms having a common point at A, and having the vertex E on BC,...
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The Training of Teachers of Mathematics for the Secondary Schools of the ...

Raymond Clare Archibald - Mathematics - 1918 - 310 pages
...in F, and F is joined to B. Prove that the angles BFA, EFA are equal. 3. Prove that parallelograms on the same base and between the same parallels are equal in area. ABCD, AEFG are two parallelograms having a common point at A, and having the vertex E on BC,...
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Bulletin, Issues 27-40

United States. Office of Education - 1918 - 1128 pages
...in F, and F is joined to B. Prove that the angles BFA, EFA are equal. 3. Prove that parallelograms on the same base and between the same parallels are equal in area. ABCD, AEFG are two parallelograms having a common point at A, and having the vertex E on BC,...
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