 | Rupert Deakin - Euclid's Elements - 1891 - 102 pages
...to one another, and the diameter bisects the parallelogram, ie divides it into two equal parts. 35. Parallelograms on the same base and between the same parallels are equal to one another. 36. Parallelograms on equal bases and between the same parallels are equal to one another.... | |
 | Peter Alexander - Thermodynamics - 1892 - 228 pages
...parallel to OX, and the lines hX', kN, Eu, L8, Da, PJTare parallel to OF. From Euclid's theorem that parallelograms on the same base and between the same parallels are equal, we get ASCD = AKQD = AKPk = AH . Ak, = ABUL = AISL =AL . Al, = AMWD = AMRm = AM. Am, = ABX'N= An VN... | |
 | University College, Galway - 1896 - 430 pages
...+ x by a? - x + 1. 5' Simplify (*+l)H (*-!)ยป. 6. Solve the equation x + 5 x - 6 x + 3 ~ x - 9' 7. Parallelograms on the same base and between the same parallels are equal in area. 8. If a straight line is bisected and also divided unequally the sum of the squares on the... | |
 | Alfred John Pearce - 1897 - 202 pages
...parallelogram, the length and perpendicular height being given. , Let ABCD be an oblique parallelogram. Now, parallelograms on the same base and between the same parallels are equal (Euc. I. 35). Therefore the area of the oblique parallelogram ABCD equals the area of the rectangle... | |
 | Northwest Territories Council of Public Instruction - 1897 - 628 pages
...with no pair parallel ; (ii) with one pair parallel ; (iii) with two pairs parallel. (J) Prove that parallelograms on the same base and between the same parallels are equal in area. I. 35. (f) Point out the uses of proposition (I) in mensuration. (d) Prove that if a square... | |
 | Seymour Eaton - 1899 - 362 pages
...therefor' the triangle ABC is equal to the triangle BCD (Proposition 4). PROPOSITION 35. THEOREM 323 Parallelograms on the same base and between the same parallels are equal to one another. Let the parallelograms ABCD, EBCF be on the same base BC, and between the same parallels... | |
 | American Association for the Advancement of Science - American periodicals - 1899 - 646 pages
...geometry, and in the third part a strict treatment of equivalence. Even Euclid, in proving his I. 35, " Parallelograms on the same base, and between the same parallels, are equal to one another," does not show that the parallelograms can be divided into pairs of pieces admitting... | |
 | American Association for the Advancement of Science - Science - 1899 - 650 pages
...geometry, and in the third part a strict treatment of equivalence. Even Euclid, in proving his I. 35, "Parallelograms on the same base, and between the same parallels, are equal to one another," does notshowthat the parallelograms can be divided into pairs of pieces admitting... | |
 | Euclid, Henry Sinclair Hall, Frederick Haller Stevens - Euclid's Elements - 1900 - 330 pages
...recognized system should be allowed, such, for example, as that given on page 11.] PROPOSITION 35. THEOREM. Parallelograms on the same base, and between the same parallels, are equal in area. DE FADEFAEDF Let the parallelograms ABCD, EBCF be on the same base BC, and between the same... | |
 | Great Britain. Parliament. House of Commons - Great Britain - 1900 - 686 pages
...the equal angles shall be equal to one another. .10. Define parallel straight lines and prove that parallelograms on the same base and between the same parallels are equal in area. 11. A square field contains 15 ac. 2 ro. 20 per.; find the length of a path crossing it diagonally.... | |
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Prove that parallelograms on the same base and between the same parallels are equal in area. 
